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topjm [15]
2 years ago
5

What are the coefficients that would balance this equation _____NaOH+____H2CO3-Na2CO3+_____H2O

Chemistry
1 answer:
FromTheMoon [43]2 years ago
4 0
I don’t see any equal signs to make it an equation. Am I missing something?
You might be interested in
The chemical formula for ferric sulfate is Fe(SO4)3. Determine the following:
Lyrx [107]

Answer :

(a) The number of sulfur atoms are, 31.61\times 10^{23}.

(b) The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(c) The number of moles of Fe_2(SO_4)_3 is, 8.63\times 10^{-3}mole

(d) The mass of the mass of Fe_2(SO_4)_3 is, 19.95\times 10^{-22}g

Explanation :

(a) As we are given the number of moles of Fe_2(SO_4)_3 is, 1.75 mole. Now we have to calculate the number of sulfur atoms.

In the Fe_2(SO_4)_3, there are 2 iron atoms, 3 sulfur atoms, 12 oxygen atoms.

As, 1 mole of Fe_2(SO_4)_3 contains 3\times 6.022\times 10^{23} number of sulfur atoms.

So, 1.75 mole of Fe_2(SO_4)_3 contains 1.75\times 3\times 6.022\times 10^{23}=31.61\times 10^{23} number of sulfur atoms.

The number of sulfur atoms are, 31.61\times 10^{23}

(b) As we are given the number of moles of Fe_2(SO_4)_3 is, 2.65 mole. Now we have to calculate the mass of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

\text{Mass of }Fe_2(SO_4)_3=2.65mole\times 399.88g/mole=1059.682g

The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(c) As we are given the mass of Fe_2(SO_4)_3 is, 3.45 grams. Now we have to calculate the moles of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

3.45g=\text{Moles of }Fe_2(SO_4)_3\times 399.88g/mole

\text{Moles of }Fe_2(SO_4)_3=8.63\times 10^{-3}mole

The number of moles of Fe_2(SO_4)_3 is, 8.63\times 10^{-3}mole

(d) As we are given the formula unit of Fe_2(SO_4)_3 is, 3. Now we have to calculate the mass of Fe_2(SO_4)_3.

As we know that 1 mole of Fe_2(SO_4)_3 contains 6.022\times 10^{23} formula unit.

Formula used :

\text{Formula unit of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}

3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}

\text{Moles of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole

Now we have to calculate the mass of Fe_2(SO_4)_3.

\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

\text{Mass of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole\times 399.88g/mole=19.95\times 10^{-22}g

The mass of the mass of Fe_2(SO_4)_3 is, 19.95\times 10^{-22}g

6 0
3 years ago
Put the steps in the process of photosynthesis in order
shepuryov [24]

Step 1-Light Dependent

CO2 and H2O enter the leaf

Step 2- Light Dependent

Light hits the pigment in the membrane of a thylakoid, splitting the H2O into O2

Step 3- Light Dependent

The electrons move down to enzymes

Step 4-Light Dependent

Sunlight hits the second pigment molecule allowing the enzymes to convert ADP to ATP and NADP+ gets converted to NADPH

Step 5-Light independent

The ATP and NADPH is used by the calvin cycle as a power source for converting carbon dioxide from the atmosphere into simple sugar glucose.

Step 6-Light independent

The calvin cycle converts 3CO2 molecules from the atmosphere to glucose

calvin cycle

The second of two major stages in photosynthesis (following the light reactions), involving atmospheric CO2 fixation and reduction of the fixed carbon into carbohydrate.

4 0
3 years ago
Electrolytic cells use electricity to cause a nonspontaneous redox reaction to occur. An electrolytic cell is constructed using
Fittoniya [83]

Answer:

At anode - {Br_2}_{(l)}

At cathode - {H_2}_{(g)}

Explanation:

Electrolysis of NaBr:

Water will exist as:

H_2O\rightleftharpoons H^++OH^-

The salt, NaBr will dissociate as:

NaBr\rightarrow Na^++Br^-

At the anode, oxidation takes place, as shown below.

{Br^-}_{(aq)}\rightarrow {Br_2}_{(l)}+2e^-

At the cathode, reduction takes place, as shown below.

2{H^+}_{(aq)}+2e^-\rightarrow {H_2}_{(g)}

4 0
3 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
11) A sample of rhenium of suspected extrasolar origin (translation: not from this solar
jarptica [38.1K]

<u>Answer:</u>

<em>Atomic number 75 is dedicated to an element named rhenium and has been given Re as its chemical name.</em>

<u>Explanation:</u>

With a really low concentration it is one of the rarest metals that is found in Earth's crust.

Like all other elements rhenium also has certain isotopes among with 185 and 187 are the most stable ones. Hence these two are the ones that are naturally available abundance is 34% and 63% respectively.

4 0
3 years ago
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