Answer:
65°C
Explanation:
Formula for calorimetry is:
Q = C . m . ΔT
Where Q is heat, C is specific heat, m is mass and ΔT is the difference between final T° and initial.
We have all data to replace.
First of all, we convert kJ to J → 4.94 kJ . 1000 J / 1 kJ = 4940 Joules
We made this conversion because the unit of C, is in J
As heat is lost, we have to think in a negative value. Let's replace:
- 4940 J = 4.18 J/ g °C . 35 g . ( Final T° - 98.8°C)
- 4940 J / (4.18 J/ g °C . 35 g) = Final T° - 98.8°C
Final T° = - 4940 J / (4.18 J/ g °C . 35 g) + 98.8°C
Final T° = 65.03 °C
Notice, that this answer has sense because as T° decreased, heat has been lost.
Experimental errors can be of two kinds: human error and analytical error. Analytical error can be corrected easily. You just have to use instruments that are of high precision. For example, instead of using the platform balance, use the analytical balance which displays 4 decimal places to be highly accurate. For the human error, this is subjective. The only way to correct human error is to be more meticulous on your data measurements.
He was brought to be believe that the earth was geocentric, meaning the earth was centered and everything orbited around it but he then published his work saying that is was heliocentric. So in the end believed in heliocentric. Let me know if this helped.
Answer:
Q = 0.144
Explanation:
- C(s) + H2O(g) ↔ CO(g) + H2(g)
reaction quotient:
- Q = [H2(g)][CO(g)] / [H2O(g)][C(s)]
∴ [C(s)] = 10.0 mol/2.50 L = 4 M
∴ [H2O(g)] = 16.0 mol/2.50 L = 6.4 M
∴ [CO(g)] = 3.30 mol/2.50 L = 1.32 M
∴ [H2(g)] = 7.00 mol/2.50 L = 2.8 M
⇒ Q = (2.8 M)(1.32 M) / (6.4 M)(4 M)
⇒ Q = 0.144
Answer:
D) 1.6 x 10⁻¹⁴
Explanation:
The solubility-product equilibrium constant for Ag₂SO₃ is given by the expression
Ksp = [Ag⁺]² [SO₃²⁻]
where [Ag⁺] and [SO₃²⁻] are the concentration of the species dissolved in solution for the equlibrium
Ag₂SO₃ (s) ⇄ 2 Ag⁺ + SO₃²⁻
we are given the concentration of Ag⁺ and from the stoichiometry of the equilibrium, the concentration of SO₃²⁻ is half that value, so
[Ag⁺]² = 3.2 x 10⁻⁵ M
[SO₃²⁻] = 3.2 x 10⁻⁵ M / 2 = 1.6 x 10⁻⁵ M
plugging these values into the solubility product constant equation we have
Ksp = (3.2 x 10⁻⁵)² x (1.6 x 10⁻⁵) = 1.6 x 10¹⁴
Therefore D is the correct answer.
