We observe that heat capacity of salted water we will find that it is less than pure water. We now that it takes less energy to increase the temperature of the salt water 1°C than pure water. Which means that the salted water heats up faster and eventually reaches to its boiling point first.
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Answer:
It is a chemical change.
Explanation:
When the electricity is off, the filament cools down to its original physical state. This physical process repeats every time the light is turned on and off. However, if the bulb is cracked and air is introduced, the oxygen in the air reacts with the tungsten filament which then undergoes a chemical change.
Answer:
Rate = k [OCl] [I]
Explanation:
OCI+r → or +CI
Experiment [OCI] M I(-M) Rate (M/s)2
1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3
2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3
3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3
4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3
The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.
In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.
In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.
The rate law is given as;
Rate = k [OCl] [I]
Answer:
The answer is C. The high solvation energy for LI+
Explanation:
LiF has lower solubility because of the high solvation energy of Li+ ion. This is due to the smaller size and very big charge compared to Cs+ ion which has a bigger size and solvent molecules easily surround it.
Solvation energy is simply the amount energy that is required to make a solute dissolve in a solvent.
The volume of chlorine gas measured at STP will be liberated by a current of 2.5 A flowing for a period of 1.8 hours through an aqueous solution of AgCl is 1.88 litre.
<h3>What is Faraday's law ?</h3>
According to Faraday's Law , During Electrolysis , The amount of substance liberated at the cathode or anode is directly proportional to the electricity that is passed through the cell.
The reaction taking place at anode is:
2Cl → Cl₂ +2e −
The total charge is calculated as
Q=I×t= 2.5×1.8×60×60 coulomb
Q = 16200 coulomb
The amount of chlorine liberated by passing 16200 coulomb of electric charge
= 16200/(2*96500)
= 0.084 mole
Volume of Cl₂ at STP is
1 mole at STP has 22.4 L of Gas
0.084 mole of Cl₂ at STP will be equal to 22.4 *0.084 = 1.88 litre of Cl₂
To know more about Faraday's Law
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