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3 years ago

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How many grams of sodium bicarbonate are needed to completely react with a 0.892 m phosphoric acid solution that contains to 45.

0 g of water and forms water, carbon dioxide, and sodium phosphate?

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

Answer:

umm idk if I was right or not

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How many moles are in a 12.0 g sample of NiC12

Nady [450]

Answer:

0.17 moles

Explanation:

In the elements of the periodic table, the atomic mass = molar mass. <u>Ex:</u> Atomic mass of Carbon is 12.01 amu which means molar mass of Carbon is also 12.01g/mol.

In order to find the # of moles in a 12 g sample of NiC-12, we will need to multiply the number of each atom by its molar mass and then add the masses of both Nickel and C-12 found in the periodic table:

Molar Mass of Ni (Nickel): 58.69 g/mol

Molar Mass of C (Carbon): 12.01 g/mol

Since there's just one atom of both Carbon and Nickel, we just add up the masses to find the molar mass of the whole compound of NiC-12.

58.69 g/mol of Nickel + 12.01 g/mol of Carbon = 70.7 g/mol of NiC-12

There's 12g of NiC-12, which is less than the molar mass of NiC-12, so the number of moles should be less than 1. In order to find the # of moles in NiC-12, we need to do some dimensional analysis:

12g NiC-12 (1 mol of NiC-12/70.7g NiC-12) = 0.17 mol of NiC-12
The grams cancel, leaving us with moles of NiC-12, so the answer is 0.17 moles of NiC-12 in a 12 g sample.

<em>P.S. C-12 or C12 just means that the Carbon atom has an atomic mass of 12amu and a molar mass of 12g/mol, or just regular carbon.</em>

5 0

2 years ago

The element Osminum has a density of 22.6 g/cm3. the mass of a block of Osmium with three sides of 1.01cmx0.223 cm x 0.648 cm is

Alika [10]

Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3

Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g

6 0

2 years ago

What does a graph representing Charles’s law show?

Juliette [100K]

<span>Volume increases at the same rate as temperature.</span>

5 0

2 years ago

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What happens at night?

Alex

Warm air other the ocean moves onshore I think

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2 years ago

A sample originally contained 1.28 g of a radioisotope. It now contains 1.12 g of its daughter isotope.

dexar [7]

The answer is 3.

<span>The relation between number of half-lives (n) and decimal amount remaining (x) can be expressed as:

</span> $(1/2) ^{n} =x$

We need to calculate n, but we need x to do that. To calculate what p<span>ercentage of a radioactive species would be found as daughter material, we must calculate what amount remained:
1.28 -</span> 1.12 = 0.16

If 1.28 is 100%, how much percent is 0.16:
1.28 : 100% = 0.16 : x
x = 12.5%
Presented as decimal amount:
x = 0.125

Now, let's implement this in the equation:

<span> $(1/2) ^{n} =0.125$
</span>
Because of the exponent, we will log both sides of the equation:
$n * log(1/2) = log(0.125)$
$n = \frac{log(0.125)}{log(1/2)}$
<span> $n = \frac{log(0.125)}{log(0.5)}$
</span> $n= \frac{-0.903}{-0.301}$
$n = 3$

Therefore, 3 half-lives have passed <span> since the sample originally formed.</span>

4 0

3 years ago

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