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2 years ago

13

AABC is isosceles. mZC = 25° and mZA = 8x - 7.

1 answer:

Orlov [11]2 years ago

6 0

Answer:

x = 4

Step-by-step explanation:

<C = <A

25° = 8x - 7

32 = 8x

x = 4

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Eight Divided by 534

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<span>Answer : 0.0149812734

8 </span>÷ 534 = 0.0149812734
Hope this Helps :)

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3 years ago

Sameera predicted that she would sell 38 blankets, but she actually sold 28 blankets. Which expression would find the percent er

antoniya [11.8K]

Solution: We are given:

Predicted Sales by Sameera $=38$

Actual Sales by Sameera $=28$

Now to find the Percent error, we have to use the below formula:

$Percent-Error= \frac{|Predicted-value - Actual-value|}{Actual-value} \times 100 \%$

$=\frac{|38-28|}{28} \times 100 \%$

$=\frac{10}{28}\times 100 \%$

$=35.71 \%$

Therefore, the percent error is $35.71 \%$

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3 years ago

Read 2 more answers

According to recent reports, Apple Inc. holds 27.6% of the Tablet Computer market. Suppose a consumer research company believes

KonstantinChe [14]

Answer:

We don't have sufficient evidence to support the claim

Step-by-step explanation:

Null hypothesis:

$H_0: p = 0.276$

Alternate hypothesis:

$H_1: p < 0.276$

The P-value is 0.3064

0.3064 probability of finding a sample proportion lower than the one found.

The p-value is higher than the significance level of 0.05, which means that there is no sufficient evidence to support the claim.

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3 years ago

When factoring to reveal the roots of the equation x² + 2x° - 9x- 18 = 0, which equations

timofeeve [1]

1 and 3 only answer is number 2

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3 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

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3 years ago