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3 years ago

find the area of a right angle triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long

Mathematics

1 answer:

Lelu [443]3 years ago

6 0

Answer:

30 cm^2

Step-by-step explanation:

a = 13 cm

b = 12 cm

using Pythagorean theorem:

a^2 = b^2 + c^2

--> c^2 = a^2 - b^2 = 13^2 - 12^2 = 169 - 144 = 25

--> c = √25 = 5

The area of that right triangle is:

S = b.c / 2 = 12 . 5 / 2 = 30 (cm^2)

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at a party 3/5 of the attendess were female . of the the female 2/5 wore earrings .what fraction of the attendees were femaleas

Nata [24]

$\frac{6}{25}$ of the attendees were females wearing earrings.

Step-by-step explanation:

As per the given information, there were $\frac{3}{5}$ females in the party.

To calculate the fraction of females wearing earrings we will do the following,

From these $\frac{3}{5}$ females, $\frac{2}{5}$ females wore earrings.

<u>This can be written in numerical form as:</u>

$\frac{2}{5}$ of $\frac{3}{5}$

---> $\frac{2}{5}$ * $\frac{3}{5}$

= $\frac{6}{25}$

So $\frac{6}{25}$ of the attendees were females wearing earrings.

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find the area of a right angle triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long​

find the area of a right angle triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long