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2 years ago

Please do provide a correct answer because other ways I will report/block you. Please be honest and help me, please.

Mathematics

1 answer:

Irina-Kira [14]2 years ago

4 0

Answer:

incomplete

Step-by-step explanation:

please send the full information, I can't see students belonging to acers

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peter is baking cookies. The recipe calls for 3/4 cups of flour. He needs to triple the recipe. How many cups of flour will he n

allochka39001 [22]

Answer:

$3 \times \frac{3}{4} = \frac{3}{1} \times \frac{3}{4}$

$\frac{3}{1} \times \frac{3}{4} = \: \: \frac{9}{4} \: or \: \: 2 \:\times \frac{1}{4}$

Step-by-step explanation:

Originally he needs 3/4 cups

If he is tripling it, he need 3 times 3/4.

You can see above since every number has a 1 under them you can write 3 as 3/1 if it make it easier dor you to understand.

Then, you multiply numerators and denominators with each other. 3 times 3 will give you 9 and 1 times 4 will give you 4.

So you got 9/4 whixh can also write as 2(times)1/4

Hope this is helps. Let me know if you have any questions.

7 0

4 years ago

Viola can work no more than 11 hours a week at her part-time job. She gets paid $7.75 per hour. Let p stand for the amount she g

Morgarella [4.7K]

The domain is 11 and the rang is $7.75.

Domain= X- values
Range= differences between the highest & lowest value

4 0

3 years ago

How to solve-3r+9=-4r+5

MakcuM [25]

Subtract 5 from both sides then you get -3r+9=-4r then add 3r to both sides then you get 9=-1r then divide both sides by -1 and you get r=-9

6 0

3 years ago

The Spanish club sold hot pretzels as a fundraiser. The pretzels normally sold for $2.00, but near the end of the sale the price

Maurinko [17]

The new price is 1.50$

5 0

3 years ago

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Studentka2010 [4]

Using the z-distribution, it is found that the needed sample sizes are:

a) 242

b) 1842

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so $z = 2.575$ .

Item a:

The estimate is:

$\pi = 0.223 - 0.189 = 0.034$

The sample size is <u>n for which M = 0.03</u>, then:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 2.575\sqrt{\frac{0.034(0.966)}{n}}$

$0.03\sqrt{n} = 2.575\sqrt{0.034(0.966)}$

$\sqrt{n} = \frac{2.575\sqrt{0.034(0.966)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.034(0.966)}}{0.03}\right)^2$

$n = 241.97$

Rounding up, a sample of 242 is needed.

Item b:

No prior estimates, hence $\pi = 0.5$ is used.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 2.575\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 2.575\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{2.575\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.5(0.5)}}{0.03}\right)^2$

$n = 1841.8$

Rounding up, a sample of 1842 is needed.

For more on the z-distribution, you can check brainly.com/question/25404151

5 0

3 years ago