Answer:

Step-by-step explanation:
Given


Required
Determine the quotient
See attachment for complete process.
First, divide 125x^3 by 5x

Write
at the top
Multiply
by 

Subtract from 125x^3 - 8
i.e.

Step 2:
Divide 50x^2 by 5x

Write
at the top
Multiply
by 

Subtract from 50x^2 - 8
i.e.

Step 3:
Divide 20x by 5x

Write
at the top
Multiply
by 

Subtract from 20x - 8
i.e.

Hence:

Answer:
ft³
Step-by-step explanation:
First, let's figure out how to get the <em>volume </em>of a sphere from its <em>surface area</em>. If r is the radius of our sphere, then
The formula for a sphere's surface area is
The formula for a sphere's volume is 
So to get from area to volume, we have to <em>divide the area by 3 </em>and then <em>multiply it by r.</em> Mathematically:

Before we solve for V though, we need to find the radius of our sphere. Thankfully, we're given the surface area -
ft² - so we can use the area formula to find that radius:

And now that we have our radius, we can put it into our volume formula to find
ft³
1.7(j-2)
Hope it helped :)
The square root of -56 is 7.4833 (feel free to round it up to 7.5)
I hope this helps you!
Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.