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2 years ago

Please do provide a correct answer because other ways I will report/block you. Please be honest and help me, please.

Mathematics

1 answer:

Irina-Kira [14]2 years ago

4 0

Answer:

incomplete

Step-by-step explanation:

please send the full information, I can't see students belonging to acers

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Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

4 years ago

Read 2 more answers

What is the value of a?

Artemon [7]

The value has to be 14

4 0

3 years ago

Guys, help me please solve this

Ganezh [65]

Answer:

3 (2)^2 + 4 / (2)

3 (4) + 4 / 2

12 + 4/ 2

16/ 2

8 0

3 years ago

pickupchik [31]

Answer:

Step-by-step explanation:

31 + 371 + 21 = 423

31/423 = 7%

8 0

2 years ago

Please help! #11 and #12

dem82 [27]

11. In attachment.

12. Look at the picture.

Answer: point B.

8 0

3 years ago