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ZanzabumX [31]
3 years ago
6

Can anyone help me wit this problem..

Mathematics
1 answer:
Ket [755]3 years ago
5 0
Use formula for the number of combinations \\C_k^n= \frac{n!}{(n-k)!k!} \\ \\n=12, k=2
\\ C_2^{12}= \frac{12!}{(12-2)!2!}= \frac{12!}{10!2!}= \frac{12\times11}{2\times1}=66
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