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3 years ago

Can anyone help me wit this problem..

1 answer:

5 0

Use formula for the number of combinations $\\C_k^n= \frac{n!}{(n-k)!k!} \\ \\n=12, k=2
\\ C_2^{12}= \frac{12!}{(12-2)!2!}= \frac{12!}{10!2!}= \frac{12\times11}{2\times1}=66$

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WHAT IS PRODUCT OF (6X+5)(X^2-2X+1)

Anettt [7]

$(6x+5)(x^2-2x+1)=6x\cdot x^2-6x\cdot2x+6x + 5\cdot x^2-5\cdot 2x+5 =\\ \\=6 x^3-12x^2+6x + 5 x^2- 10x+5 =6 x^3-7x^2-4x+5$

4 0

3 years ago

> 40 cm out of 3.5m .

vovikov84 [41]

Answer:

Your answer is 11.42

Step-by-step explanation:

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3 0

3 years ago

Find the difference between the two numbers on a number line -7 1/5 and -4 2/3

morpeh [17]

Answer:

do the rest urself

Step-by-step explanation:

-7 1/5= -36/5

-4 2/3= -14/3

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6 0

3 years ago

Let a = x2 + 4. Use a to find the solutions for the following equation:

Zepler [3.9K]

The solutions for x are -2, 0, 2

Solution:

Given that,

$\text { Let } a = x^2 + 4$

Given equation is:

$(x^2 + 4)^2 + 32 = 12x^2 + 48$

$(x^2 + 4)^2 + 32 = 12(x^2 + 4)$

$\text { Subtsitute } a = x^2 + 4 \text{ in above equation }$

$a^2 + 32 = 12a\\\\a^2 -12a + 32 = 0$

$\text{ Let us factorize the above equation }\\\\\text{ Splitting the middle term -12a as -4a - 8a we get, }$

$a^2 -4a - 8a + 32 = 0$

Taking "a" as common term from first two terms and taking "-8" as common from last two terms

$a(a-4)-8(a - 4) = 0$

$\text{Taking (a - 4) as common term, }\\\\(a - 4)(a - 8) = 0$

$\text{Equating to zero we get, }\\\\(a - 4) = 0 \text{ or } (a - 8) = 0\\\\a = 4 \text{ or } a = 8$

$\text{Now substitute the value of a = 8 and a = 4 in: }\\\\a = x^2 + 4$

$\text{ For a = 8: }\\\\a = x^2 + 4\\\\8 = x^2 + 4\\\\x^2 = 4\\\\x = \pm2\\\\x = +2 \text{ or } -2$

$\text{For a = 4: }\\\\a = x^2 + 4\\\\4 = x^2 + 4\\\\x = 0$

$\text{Thus solutions of } x \text{ are: }\\\\x = 0 \text{ or } x = 2 \text{ or } x = -2$

8 0

3 years ago

what is is 7 *10+ 7 i need to now please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

-Dominant- [34]

7*10= 70+7=77

so ur answer is 77

3 0

3 years ago

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