Question

An experiment was conducted to test the effect of a new cholesterol medicine. Fifteen people were treated with medicine X and 15 with medicine Y for a month; then the subjects' cholesterol level was measured. A significance test was conducted at the α = 0.01 level for the mean difference in cholesterol levels between medicine X and medicine Y. The test resulted in t = 2.73 and p = 0.003. If the alternative hypothesis in question was Ha: μX − μY ≠ 0, where μX equals the mean cholesterol level for subjects taking medicine X and μY equals the mean cholesterol level for subjects taking medicine Y, what conclusion can be drawn?

Answer 1

Considering the hypothesis tested and the p-value of the test, the correct option is given by:

There is sufficient evidence that there is a difference in mean cholesterol level when using medicine X and medicine Y.

What are the hypothesis tested?

At the null hypothesis, it is tested if there is no difference between the cholesterol levels, that is:

H₀:Hₓ-H

At the alternative hypothesis it is tested if there is a difference, hence:

H₀:Hₓ-H≠0

The p-value is of 0.003 < 0.01, hence we reject the null hypothesis and conclude that there has was a difference, hence the correct option is given by:

There is sufficient evidence that there is a difference in mean cholesterol level when using medicine X and medicine Y.

More can be learned about hypothesis tests at brainly.com/question/26454209

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