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Leya [2.2K]
3 years ago
8

What is the missing statement in step 3 of the proof? mAngle1 = mAngle2 mAngle1 + mAngle2 = 90° mAngle2 = mAngle3 mAngle2 + mAng

le3 = 180°
Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

answer is 90

if m^2=m^3

then, 90+90=180

Step-by-step explanation:

Shkiper50 [21]3 years ago
4 0

Answer:

B. m<1 + m<2 = 90

Step-by-step explanation:

Just had the question.

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Which function do you evaluate first in g(f(x))? f(x) g(x) f(g(x))
Mazyrski [523]

For the composite function g(f(x)), the function f(x) goes first in terms of evaluation. This is the inner most function. You would read it from right to left in terms of determining the order of evaluation.

4 0
3 years ago
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Write the equation of a line with the slope of -7 and passing through the point (2, 2).​
grandymaker [24]

Answer:

y=-7x+16

Step-by-step explanation:

y-y=m(x-x1)

y-2=-7(x-2)

y-2=-7x+14

+2 +2

y=-7x+16

5 0
3 years ago
Noah says to find 20% of a number he divides the number by 5. Is this true explain your answer
Nutka1998 [239]

Answer:

yes

Step-by-step explanation:

note that 20% = \frac{20}{100} = \frac{1}{5}

Hence to find 20% of a number, dividing the number by 5 is correct

20% of £30 = \frac{30}{5} = £6


5 0
3 years ago
Caleb has shelves that hold
kkurt [141]

Answer:

10%

Step-by-step explanation:

if he has 60 boxes then it would be 60/600

simplify that to 6/60 which further simplifies to 1/10 which is 10%

5 0
3 years ago
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A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
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