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Sergeeva-Olga [200]
3 years ago
11

A generator runs for 2 1/2 hours and uses 4 3/8 gal of fuel per hour .How many gallons of fuel did the generator use in total? E

nter your answer as a mixed number in simplest form.
Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0
4 3/8  x 2 = 8 6/8 
4 3/8 divide 2 = 3/32 
6/8 x 4 = 24/32 
24/32 + 3/32 = 27/32 
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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
3 years ago
In a line of students ,Jenna is number 8.The teacher says the rule for a number pattern is add4.The first term 7.What number sho
balandron [24]
1. You have that the rule for a number pattern is add 4 and the <span>first term is 7.

 2. Let's call "n" to the number in the line where each student is. Then, you can express this as below:

 4n+7

 3. So, you have:

 Student N°1=4(1)+7=11
</span> Student N°2=4(2)+7=15
 Student N°3=4(3)+7=19
 Student N°4=4(4)+7=23
 Student N°5=4(5)+7=27
 Student N°6=4(6)+7=31
 Student N°7=4(7)+7=35
 Student N°8=4(8)+7=39
<span>
 What number should Jenna say?

 The answer is: 39</span>
4 0
3 years ago
The lines shown below are parallel.if the green line has a slope of -1/2, what is the slope of the red line?
Delvig [45]

The anwser is D

because it is very easy


4 0
3 years ago
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Mr. Grant spent 8.40 to place an adin the newspapers.the price included a one time fee of 6.00 pulse 0.08 per word.which method
Sladkaya [172]
Your answer is 0048.00
5 0
3 years ago
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