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Goryan [66]
2 years ago
13

1. A single coin is flipped four times. What do you think is the most likely outcome?

Physics
1 answer:
mel-nik [20]2 years ago
6 0

Answer:F. all are equally likely

Explanation:

F. because there is no way to tell if or what the persentage of tails to heads could be.

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Which action would increase the strength of the electric force between the ballon and the water
OLga [1]

Complete question is;

Which action would increase the strength of the electric force between the balloon and the water?

A. Holding a magnet near the stream of water

B. Holding the balloon closer to the stream of water

C. Holding a magnet near the balloon

D. Moving the balloon farther away from the stream of water

Answer:

B. Holding the balloon closer to the stream of water

Explanation:

When we take a charged balloon near water, what happens is that it makes electrons to be pushed away which in turn leaves the area to be positively charged. This area is now attracted to the balloon and thus the strength of the electric force between the balloon and the water is increased.

8 0
3 years ago
A 250-kN railroad car A is traveling at 40 m/s while a 550-kN freight car B is traveling at 10 m/s (both cars heading to the rig
Damm [24]

Answer:

the maximum deformation undergone by the spring = 47.46 cm

Explanation:

Using conservation of  momentum:

m_Av_A + m_Bv_B = (m_A+m_B )v

where:

m_A = \frac{250\ kN}{g}

v_A = 40

m_B = \frac{550\ kN}{g}

v_B =10

Then;

m_Av_A + m_Bv_B = (m_A+m_B )v

\frac{250*10^3}{9.81}*40 + \frac{550*10^3}{9.81}*10 = (\frac{800*10^3}{9.81} )v

1580020.387 = 81549.43935 \ v

v = \frac{1580020.387}{81549.43935}

v = 19.375 m/s

However ; using conservation of energy to determine the maximum deformation undergone by the spring ; we have:

\frac{1}{2} [m_Av_A^2 +m_Bv_B^2] =\frac{1}{2}[(m_A+m_B)v^2 + kx^2]

[m_Av_A^2 +m_Bv_B^2] =[(m_A+m_B)v^2 + kx^2]

[\frac{250*10^3}{9.81}*40^2 + \frac{550*10^3}{9.81}*10^2] =[ (\frac{800*10^3}{9.81} )*19.375^2 + 70 *10^6 \ * x^2]

x = 0.4746 m

x = 47.46 cm

Thus,  the maximum deformation undergone by the spring = 47.46 cm

3 0
4 years ago
Read 2 more answers
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