Answer:
more than 51.45 N
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<u>We are given:</u>
Mass of the television = 15 kg
Coefficient of Static friction = 0.35
<u>Minimum force required to move the television:</u>
<u>Normal Force:</u>
We know that the normal force is equal and opposite to the Weight of the television
Weight of the television = Mg
[<em>where m is the mass and g is the acceleration due to gravity</em>]
Weight = 15 * 9.8
Weight = 147 N
<u>Force of Friction:</u>
We are given the coefficient of Friction = 0.35
We know that coefficient of Friction = Force of friction / Normal Force
<em>replacing the variables</em>
0.35 = Force of Friction / 147
Force of Friction = 147 * 0.35 [<em>multiplying both sides by 147</em>]
Force of Friction = 51.45 N
Since a force of 51.45 N is will be applied opposite to the direction of application of Force, the television will only move when we apply more force than 51.45 N
C- Electrons are transferred as clothes rub against each other in the dryer.
Rolling resistance, sometimes called rolling friction or rolling drag, is the force resisting the motion when a body (such as a ball, tire, or wheel) rolls on a surface.
At Z ... slowest speed
At Y ... fastest speed
At X ... medium speed
Wherever it is in its orbit, the line from the planet to the Sun smears over the same amount of area every second.
That's Kepler's second law of planetary motion.
The reason this happens is: That's how gravity works. (A better explanation is available, but first you have to be able to twirl calculus and solid geometry in the air on long sticks.)
Answer:
Explanation:
A ) The spheres are non conducting , charge will not move on the surface so neutralization of charge by + ve and - ve charge is not possible. Charges will remain intact on them . The electric field inside them will be zero . Electric field outside shell will not be spherically symmetrical . Lines of force will emanate from the surface of positively charged shell outwardly oriented and end at negatively charged shell .
B )
distance between the centres of spherical shell
= 2 a
potential energy of charges
= k q₁ x q₂ / R
= k x - Q x Q / ( 2a )
= - k Q²/ 2a
So work needed to separate them to infinity will be equal to
= k Q²/ 2a
