All categories

3 years ago

Determine the kinetic energy of 650 kg roller coaster car that is moving with a speed of 20.0 miles per second?

Physics

1 answer:

mestny [16]3 years ago

4 0

Answer:Ek=673.109 kJ

Explanation:

Use equation for Kinetic energy: Ek=m*V²/2

m=650 kg (mass of roller coaster)

V=20.0Miles/s=20.0*1.609m/s=32.18m/s

Ek=m*V²/2

Ek=650kg*(32.18m/s)²

Ek=(650kg*1053.55m²/s²)/2

Ek=673 108.8 J

Ek=673.109 kJ

You might be interested in

A person on a diet loses 1.6 kg in a week. How many micrograms/second (µg/s) are lost?

Ivan

Based on the given values above, in order for us to get the answer, we need to convert the units first. So in 1 kilogram, there is 1,000,000 micrograms. In this case, 1.6 kilograms is 1,600,000 micrograms. For the week to seconds, 1 week is equivalent to 604,800 seconds. Therefore, 1,600,000 micrograms/604,800 seconds. So we are going to simplify this. So it would be 2.65<span>µg/s. Hope this answers your question.</span>

8 0

3 years ago

A solid of density 8000 kgm.. weighs 0.8 kgf in air. When it is completely

ad-work [718]

Answer:<em> 0.5kg</em>

Explanation:

5 0

3 years ago

A tank is 10 m long, 8 m wide, 4 m high, and contains kerosene with density 820 kg/m3 to a depth of 3.5 m. (Use 9.8 m/s2 for the

Alexxandr [17]

Answer:

28,126pascal

Explanation:

Hydrostatic pressure exerted on the bottom of the tank can be calculated using the formula

P = hpg where;

h is the depth of the tank = 3.5m

p is the density of the kerosene = 820kg/m³

g is the acceleration due to gravity = 9.8m/s²

Substituting the values into the formula we have;

P = 3.5×820×9.8

P = 28,126Pascal

5 0

4 years ago

What are the Standard System of unit

Natalija [7]

Answer:

Explanation:

6 0

3 years ago

You drag a suitcase of mass 8.2 kg with a force of f at an angle 41.9 ◦ with respect to the horizontal along a surface with kine

DedPeter [7]

Answer:

35.6 N

Explanation:

We can consider only the forces acting along the horizontal direction to solve the problem.

There are two forces acting along the horizontal direction:

- The horizontal component of the pushing force, which is given by

$F_x = F cos \theta$

with $\theta=41.9^{\circ}$

- The frictional force, whose magnitude is

$F_f = \mu mg$

where $\mu=0.33$ , m=8.2 kg and g=9.8 m/s^2.

The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:

$F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N$

8 0

3 years ago