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3 years ago

Calculating ph how is ph related to the concentration of hydronium ions. True or False

1 answer:

7 0

I think this is TRUE. Ph is calculating the acidic acids in water. And you need to know the concentration of hydronium ions. Hope this helped !

You might be interested in

Which of the following regions contains the primary visual cortex?

ehidna [41]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices that can be found from other sources:

a. frontal lobe
b. temporal lobe
c. occipital lobe
d. parietal lobe

The answer C occipital lobe

5 0

2 years ago

An ac generator provides emf to a resistive load in a remote factory over a two-cable transmission line. At the factory a step-

Nataliya [291]

Answer:

a) 1.875 volts

b) 5.86 W

Explanation:

Given data:

transmission line resistance = 0.30/cable

power of the generator = 250 kW

if Vt = 80 kV

a) Determine the decrease V along the transmission line

Rms current in cable = P / Vt = 250 / 80 = 3.125 amps

hence the rms voltage drop ( Δrmsvoltage )

Δrmsvoltage = Irms* R = 3.125 * 2 * 0.30 = 1.875 volts

b) Determine the rate Pd at which energy is dissipated in line as thermal energy

Pd = $I^2rms*R$

= 3.125^2 * 2* 0.30 = 5.86 W

3 0

2 years ago

How are sound waves different from light (and other electromagnetic, waves?

Blababa [14]

Sound waves travel faster

8 0

3 years ago

Q/C An undersea earthquake or a landslide can produce an ocean wave of short duration carrying great energy, called a tsunami. W

iragen [17]

The amplitude $A_{2}$ is 8.307 m

When describing the peak value of a quantity, such as the level of sound waves or the power and voltage in electrical and electronic systems, the term amplitude is employed. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

As we previously discussed in the concept session, the square root of the water's speed is inversely related to the amplitude of its waves.

$A\alpha\frac{1}{\sqrt{v} }$

Solve for first case:

$A_{1}=\frac{1}{\sqrt{v_{1} } }$

Solve for second case:

$A_{2}=\frac{1}{\sqrt{v_{2} } }$

So, the two equations is equal

$A^{2} _{1} v_{1} = A^{2} _{2} v_{2}$

$=A^{2} _{2} \sqrt{g d_{2} }$

Rearrange and solve for the amplitude $A_{2}$ :

$A_{2} =\sqrt{\frac{A^{2}_{1} v_{1} }{v_{2} } }$

$=\sqrt{\frac{A^{2}_{1} v_{1} }{\sqrt{g d_{2} } } }$

$=\sqrt{\frac{(1.8m)^{2} X200 m/s }{\sqrt{9.8m/s^{2}X9 m } } }$

= 8.307 m

So, The amplitude $A_{2}$ is 8.307 m.

Learn more about amplitude here:

brainly.com/question/3613222

#SPJ4

7 0

2 years ago

A spherical balloon is inflated with gas at the rate of 500 cubic centimeters per minute. How fast is the radius of the balloon

Nookie1986 [14]

Answer:

Explanation:

The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.

Using chain rule to express dV/dt;

dV/dt = dV/dr*dr/dt

dr/dt is the rate at which the radius of the gallon is increasing.

From the formula, dV/dr = 3(4/3πr^3-1))

dV/dr = 4πr²

dV/dt = 4πr² *dr/dt

500 = 4πr² *dr/dt

If radius r = 40;

500 = 4π(40)² *dr/dt

500 = 6400π*dr/dt

dr/dt = 500/6400π

dr/dt = 5/64π

dr/dt = 0.245cm/min

Hence, the radius of the balloon is increasing at the rate of 0.245cm/min

8 0

3 years ago