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3 years ago

Calculating ph how is ph related to the concentration of hydronium ions. True or False

1 answer:

7 0

I think this is TRUE. Ph is calculating the acidic acids in water. And you need to know the concentration of hydronium ions. Hope this helped !

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In which of the following does personality psychology specialize?

ValentinkaMS [17]

B, Studying how ones' character changes over time... That's the only one that has to deal with personality.

5 0

3 years ago

Read 2 more answers

Photosynthesis transforms molecules of water and carbon dioxide into Molecules of?

brilliants [131]

Into molecules of sugar and oxygen.
The complete reaction of the photosynthesis is in fact:
$6CO_2+6H_2O \rightarrow C_6H_{12}O_6+6O_2$
and the energy of the light coming from the sun is also used to make the reaction possible.

7 0

4 years ago

Cat walks 100 m East, then turns around and walks 25 m west. What is the cats displacement?

kvasek [131]

Answer:

Explanation:

If a cat walk 100m East, this means that it is walking in the positive x direction, the distance will therefore be +100m

If it turns around and walks 25 m west, the direction of movement is in the negative x direction i.e -25m

Taking the sum;

Displacement = +100m - 25m

Displacement of the cat = 75m

hence the cats displacement is 75m

8 0

3 years ago

Which is true about the way air flows

JulsSmile [24]

Answer:

A High-to-Low

Explanation:

its like water running down a hill.

4 0

3 years ago

A Brayton cycle has air into the compressor at 95 kPa, 290 K, and has an efficiency of 50%. The exhaust temperature is 675 K. Fi

motikmotik

Answer:

The specific heat addition is 773.1 kJ/kg

Explanation:

from table A.5 we get the properties of air:

k=specific heat ratio=1.4

cp=specific heat at constant pressure=1.004 kJ/kg*K

We calculate the pressure range of the Brayton cycle, as follows

n=1-(1/(P2/P1)^(k-1)/k))

where n=thermal efficiency=0.5. Clearing P2/P1 and replacing values:

P2/P1=(1/0.5)^(1.4/0.4)=11.31

the temperature of the air at state 2 is equal to:

P2/P1=(T2/T1)^(k/k-1)

where T1 is the temperature of the air enters the compressor. Clearing T2

11.31=(T2/290)^(1.4/(1.4-1))

T2=580K

The temperature of the air at state 3 is equal to:

P2/P1=(T3/T4)^(k/(k-1))

11.31=(T3/675)^(1.4/(1.4-1))

T3=1350K

The specific heat addition is equal to:

q=Cp*(T3-T2)=1.004*(1350-580)=773.1 kJ/kg

3 0

3 years ago