Answer:
Explanation:
We shall represent each displacement by vectors . i will represent east , -i west , j north and - j south .
Rhino walks 1.5 km west on day 1.
D₁ = - 1.5 i
The rhino then moves 0.7 km on a straight line in a direction of 15o east of north toward ground camera B
D₂ = .7 sin15 i + .7cos15 j
On the second day, the rhino moves 2.5 km directly south
D₃ = - 2.5 j
D = D₁ + D₂ + D₃
= - 1.5 i + .7 sin15 i + .7cos15 j - 2.5 j
= - 1.5 i + .181 i + .676 j - 2.5 j
= - 1.32 i - 1.824 j
magnitude of total displacement
= √ (1.32² +1.824²
= 2.25 km
For direction we shall calculate slope with x axis
Tanθ = - 1.824 / - 1.32
= 54°
So rhino will be towards 54° south of west as both x and y coordinates are negative.
Assuming air as ideal gas and amount of air in no of moles is known then by gas law,
PV= nRT
Pressure is constant
P* (change in volume) = nR* (change in temperature)
Answer:
Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest. Fluid friction occurs in fluids, which are liquids or gases.
Explanation: