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BARSIC [14]
3 years ago
10

1. Jake drew this rectangle and colored it in this pattern.​

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

2:3

Step-by-step explanation:

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Find the average of the following numbers. -100 and 102.
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The average is the sum of the numbers divided by the quantity of numbers.

-100 + 102 =2

2/2 = 1

The average is 1

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3 years ago
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Please help me with this question
777dan777 [17]

Answer:

51

Step-by-step explanation:

102 divided by 2 is 51

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Vijay has a collection of 50 number cubes that are each 1 cubic inch. He finds a box that is 2 inches high. He fits 10 cubes int
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Answer:

Vijay cannot fit all the cubes into the box, he can only fit 20 cubes into the box

10 x 2 = 20 cubes

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3 years ago
Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

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3 years ago
FREE BRAINLY AND 50 PTS!! MIGHT BE EASY
Thepotemich [5.8K]
> and = with line through it
8 0
2 years ago
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