Mr. Salazar was making a BBQ brisket. The brisket weighed 4 pounds. How many ounces did the brisket weigh?

Find the radius of a circle with a circumference of 35 pie yards

natita [175]

Answer:

Using the formula

C=2πr

Solving for r

r=C

2π=35

2·π≈5.57042

Step-by-step explanation:

8 0

2 years ago

Martin ordered a pizza with a 16-inch diameter. Ricky ordered a pizza with a 20-inch diameter. What is the approximate differenc

In-s [12.5K]

Answer:

the difference in diamante r is it is 4 inches bigger than the 16 inch.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

4 0

2 years ago

A card is drawn from a standard deck of 52 playing cards. If the card is a club, a fair coin is flipped 9 times and the number o

olasank [31]

Answer: There are 18 elements in the sample space for this experiment

Step-by-step explanation:

Total cards = 52

Total outcomes on tossing a coin = 2 [1 head , 1 tail]

If the card is a club, a fair coin is flipped 9 times and the number of heads flipped is noted (but card drawn is not noted)).

Possible outcomes for heads = 0,1,2,...,9

So sample space for this event = {0,1,2,3,4,5,6,7,8,9}   (Total 10 elements )  (i)

If it is not a club, the coin is only flipped 3 times, but this time the result of each flip is noted(but card drawn is not noted).

Sample space with all possible outcomes ={TTT,TTH, THT, HTT, HTH,HHT,THH,HHH} (Total 18 elements ) (ii)

From (i) and (ii), Total elements in the sample space for this experiment = 10+8 = 18

Hence, there are 18 elements in the sample space for this experiment

4 0

3 years ago

How do u solve y=2/3x-4

poizon [28]

The answer is 2 y= 2 so 3•2=6 6-4=2

4 0

3 years ago