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sertanlavr [38]
2 years ago
7

Solve this 4 ∙ 7 1/2 ∙ 1 3/5

Mathematics
1 answer:
bixtya [17]2 years ago
6 0

Step-by-step explanation:

= 7 \frac{1}{2} .1 \frac{3}{5}

=  \frac{  \red{\cancel{15}}}{ \blue{ \cancel{2}}} . \frac{  \blue{\cancel{8}}}{  \red{\cancel{5}}}

=  \frac{3}{1} . \frac{4}{1}

= 12

\:

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Which strategy best explains how to solve this problem? Rebecca bought a meal and two snacks for lunch each day. The meal cost $
Fittoniya [83]
Given:
Cost of lunch per day = 1 meal and 2 snacks

C = 5.5 + 2(0.75) = 5.5 + 1.5 = 7

7 * 12 days = 84

Based on the choices, the best strategy would be:

<span> A. Make a table. Write the numbers 1 to 12 in the top row of the table (the number of days). In the first box on the second row, write $7. This is how much Rebecca spends in 1 day. In each of the next boxes in the second row, write the amount Rebecca spends by adding $7 to the previous amount. The answer in box 12 is the total amount Rebecca spent after 12 days.</span>

6 0
3 years ago
You might even think it’s not a thing for a 11 year-old, but I got this as my assignment today: 6.22222267/2.1 x 1/2 of 98... Th
lana [24]

Answer to the question:

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4 0
3 years ago
HighTech Inc. randomly tests its employees about company policies. Last year in the 560 random tests conducted, 26 employees fai
Tanzania [10]

Answer:

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

560 random tests conducted, 26 employees failed the test. This means that n = 560, \pi = \frac{26}{560} = 0.046

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.33.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 - 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.025

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 + 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.067

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

5 0
4 years ago
I need to know if this is correct
vitfil [10]

i thinks its correct.

3 0
3 years ago
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Jlenok [28]

Answer:

sin B= 0.5678,

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B=34.59°

3 0
3 years ago
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