I’m so confused what are u trying to ask
We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
Since Seina is 4cm taller, her height is h+4.
Answer:
Correct answer: h = 3/5 or y = 3/5
Step-by-step explanation:
Given:
h(x) = (3x² - 9x - 4) / (5x² - 4x + 8)
h = lim x -> ∞ (3x² - 9x - 4) / (5x² - 4x + 8) the numerator and denominator will be divided by x² and get
h = lim x -> ∞ (3 - 9(1/x) - 4 (1/x²)) / (5 - 4(1/x) + 8 (1/x²)
The terms 1/x and 1/x² when x strives ∞ they strives 0
x -> ∞ ⇒ 1/x -> 0 and x -> ∞ ⇒ 1/x² -> 0
h = (3 - 0 - 0) / (5 - 0 + 0)
Horizontal asymptote is h = 3/5 or y = 3/5
God is with you!!!
Answer:
since 0=noon
and 15 secs=25% of a min
plot the point on the very first line to the right of 0
(the tiny line)
Step-by-step explanation:
