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earnstyle [38]
2 years ago
9

Which number sentence is not true?

Mathematics
1 answer:
Burka [1]2 years ago
8 0

Answer:

Option B

Step-by-step explanation:

|-1| \neq -1

|-1| = 1

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I have included a picture of the equation <br><br>​
Alchen [17]

Answer:

it's c , x= 1.5 or -4

2x^2 + 5x - 12 = 0

First factor the left side of the equation

(2x-3)(x+4)=0

Second, set the factors equal to 0

2x-3=0 or x+4=0

 +3  +3       -4  -4

2x=3           -4

divide both side by 2 and you get 3/2 which equals 1.5

x=1.5 or x= -4

3 0
2 years ago
Kyra was building a bed for her dollhouse. She used her bed, which is 4 feet × 5 feet, as a guide. She scaled down the dimension
Crank
The dimensions would have to be 20 x 5 as the model holds the same amount for each side, and because 5 is larger than 4 its used as the models stand.
Hope it helps! :)
5 0
3 years ago
Explain whether the following given sets are closed under addition:
Ivan

Answer:

Step-by-step explanation:

a) Yes.

\forall\ a,b\ \in\ B,\ a+b\in B\ (since\ 0+0=0)

b) Yes

W=\{0,1,2,3,..,\}\ (whole\ numbers)\\\forall\ a,b\ \in\ 3W,\ a+b\in 3W\\since:\\a\ \in\ 3W \Longrightarrow\ \exists\ k_1\in W | a=3*k_1\\\\b\ \in\ 3W \Longrightarrow\ \exists\ k_2\in W | b=3*k_2\\\\a+b=3*k_1+3*k_2=3*(k_1+k_2) \in 3W\\

c) Yes

\forall n\ \in\ \mathbb{N}: \Longrightarrow\ n+1 \in\ \mathbb{N}\\

d) No

3\in V , 3+3=6\notin V\\

7 0
3 years ago
What is the standard form of <br> Y=2/5x+2
Romashka-Z-Leto [24]

The answer to your question is -10

7 0
3 years ago
Read 2 more answers
9mph in still water it takes 5hrs longer to travel 74 miles upstream than downstream find the rate of current and round to neare
prohojiy [21]

Answer:

The rate of current is 2.5 mph.

Step-by-step explanation:

The speed in the water when current is absent is 9 mph.

If the speed of the current is v mph then the upstream speed is (9 - v) mph and the downstream speed is (9 + v) mph.

Now, it takes 5 hours longer to travel 74 miles upstream than down stream, then we can write the equation as  

\frac{74}{9 - v} - \frac{74}{9 + v} = 5

⇒ \frac{2v}{81 - v^{2} } = \frac{5}{74}

⇒ 148v = 405 - 5v²

⇒ 5v² + 148v - 405 = 0

Applying Sridhar Acharya's formula we can write  

v = \frac{-148 + \sqrt{148^{2} - 4(5)(-405) }  }{2(5)} (Neglecting the negative root)

⇒ v = \frac{- 148 + 173.2166}{10} = 2.5 mph (Rounded to the nearest 10th) (Answer)

7 0
3 years ago
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