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2 years ago

Please help with the 4/5 problems:) I completely forgot how to do this! *please show work on how you got your answer!**

Mathematics

1 answer:

postnew [5]2 years ago

3 0

Solve for Volume by Space. All physical objects occupy space, and you can find the volume for some of them by measuring their physical dimensions. ...
Solve for Volume by Density and Mass. Density is defined as an object's mass per a given unit of volume.

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LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the

Semmy [17]

Answer:

The wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ East of North with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector $\overrightarrow{DD'}$ is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

$|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)$

and the direction is $\alpha$ east of north as shown in the figure,

$\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)$

From the figure,

$|AB|=|OA-OB|$

$\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|$

$\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|$

$\Rightarrow |AB|=45.52$ miles

Again, $|PQ|=|OP-OQ|$

$\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=46.42$ miles

Now, from equations (i) and (ii), we have

$|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01$ miles, and

$\tan \alpha=\frac{|46.42|}{|45.52|}$

$\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}$

Hence, the wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ E astof North with respect to the destination point.

5 0

3 years ago

Which represents the polynomial written in standard form? 4m – 2m4 – 6m2 + 9

zmey [24]

If you would like to write the polynomial in standard form, you can do this like this:

4m - 2m^4 - 6m^2 + 9

Writing the polynomial in standard form means that you have to write the terms by descending degree:
- 2m^4 - 6m^2 + 4m + 9

The correct result would be - 2m^4 - 6m^2 + 4m + 9.

5 0

3 years ago

Read 2 more answers

11. In AWTY, if mZW is five less than twice mZY and mZX is 21 more than m_Y find the measure

wolverine [178]

9514 1404 393

Answer:

angles (W, X, Y) = (77°, 62°, 41°)

Step-by-step explanation:

Given:

ΔWZY

∠W = 2(∠Y) -5°

∠X = ∠Y +21°

Find:

∠X, ∠Y, ∠W

Solution:

Using angle measures in degrees, we have ...

∠X + ∠Y + ∠Z = 180

(∠Y +21) +∠Y + (2(∠Y) -5) = 180

4(∠Y) +16 = 180 . . . . . simplify

∠Y +4 = 45 . . . . . . . . . divide by 4

∠Y = 41 . . . . . . . . . . . . subtract 4

∠W = 2(41) -5 = 77

∠X = 41 +21 = 62

The angle measures of angles (W, X, Y) are (77°, 62°, 41°), respectively.

7 0

3 years ago

Find the measure of angle A

Ray Of Light [21]

In the fist you have to know: any angle opposite the head is equal in measurement.
so now we know one angle in the triangle it is 82
All corners of the triangle are equal 180
so we have to do this 180-82=98
so we have to collection (4x+8)+(8x-6)=98
12x+2=98
12x=96
x=8
4(8)+8=40
the answer is 40

8 0

3 years ago

Lim wrote several pairs of values that he thought were equivalent. Which of his equations is correct?

Annette [7]

Answer:

I believe the correct answer would be A: 3/5 = 60

Step-by-step explanation:

Firstly, the second option is wrong because 0.06 would be 6 hundredths, so that is wrong, the third option would be incorrect because 0.002 would equal 2 thousandths so that is also wrong, and the fourth option would be 25% instead of 75%, so your answer should be A.

7 0

2 years ago