f(x) increase by a factor of 3
Explanation:
Given that f(x)= 3* and the interval is x=4 to x=57
Now we put the value for x is 4 to 57 then value of f(x) increase with the multiply of 3.
Because the x is multiplied with 3 i.e., 3*
So f(x) increase by a factor of 3.
If we put x=4, then f(x)= 12 (∵ 3×4=12)
If we put x=5, the f(x)= 15 (∵ 3×5=15)
If we put x=6,the f(x)= 18 (∵ 3×6=18)
similarly., values of x= 7,8,9,...155.
Then,
If we put x=56, the f(x)=168
This process will continue until f(x)=171 for x=57.
Answer:
basically multiply the prices by how much they filled up. That should give the answer.
Step-by-step explanation:
It'd be a lot easier to help you if you'd share the answer graphs.
Just so that you know:
<span>f(x) = log(x + 3) + 1 can be graphed as follows:
</span>
1. Graph y = log x. This function's domain is x>0. It begins in Quadrant IV and ends in Quadrant I. It intercepts the x-axis at (1,0).
2. Now move the entire graph 1 unit to the left. This gives you the graph of y = log (x+1).
3. Now translate this entire graph up 3 units. This gives you the graph of <span>f(x) = log(x + 3) + 1.</span>
