Which of the following is not considered a flow in supply chains?

During a traceroute, which action does a router perform to the value in the Time To Live (TTL) field?

Sladkaya [172]

Answer:

<em>During a traceroute, the router decreases the Time To Live values of the packet sent from the traceroute by one during routing, discards the packets whose Time To Live values have reached zero, returning the ICMP error message ICMP time exceeded.</em>

Explanation:

Traceroute performs a route tracing function in a network. It is a network diagnostic commands that shows the path followed, and measures the transit delays of packets across an Internet Protocol (IP) network, from the source to the destination, and also reports the IP address of all the routers it pinged along its path. During this process, the traceroute sends packets with Time To Live values that increases steadily from packet to packet; the process is started with Time To Live value of one. <em>At the routers, the Time To Live values of the packets is gradually decreased by one during routing, and the packets whose Time To Live values have reached zero are discarded, returning the ICMP error message ICMP Time Exceeded</em>

7 0

3 years ago

Consider the following statements: #include #include class Temporary { private: string description; double first; double second;

Anna007 [38]

#include <iostream>

#include <iomanip>

using namespace std;

class temporary

{

public:

void set(string, double, double);

void print();

double manipulate ();

void get (string&, double&, double&);

void setDescription(string);

void setFirst(double);

void setSecond(double);

string getDescription() const;

double getFirst () const;

double getSecond () const;

temporary(string = "", double = 0.0, double = 0.0);

private:

string description;

double first;

double second;

};

void temporary::set(string a, double dblA, double dblB)

{

description = a;

first = dblA;

second = dblB;

}

void temporary::print()

{

cout << "\nDescription: " << left << setw(20) << description << endl <<

" first: " << fixed << setw(10) << setprecision(2) << first << endl <<

" second: " << fixed << setw(10) << setprecision(2) << second << endl;

}

double temporary::manipulate()

{

return first / 3.0 + second / 4.0;

}

void temporary::get(string& strDesc, double& dblFirst, double& dblSecond)

{

strDesc = description;

dblFirst = first;

dblSecond = second;

}

temporary::temporary(string d, double a, double b) : description(d), first(a), second(b) {}

void temporary::setFirst(double dblFirst){first = dblFirst;}

void temporary::setSecond(double dblSecond){second = dblSecond;}

void temporary::setDescription(string desc){description = desc;}

string temporary::getDescription() const {return description;}

double temporary::getFirst () const{return first;}

double temporary::getSecond () const {return second;}

int main()

{

cout << "temporary a;";

temporary a;

a.print();

cout << "a.setFirst(3.0): ";

a.setFirst(3.0);

a.print();

cout << "a.setSecond(4.5): ";

a.setSecond(4.5);

a.print();

cout << "a.setDescription(\"Picture Frame\") ";

a.setDescription("Picture Frame");

a.print();

cout << "a.print(): ";

a.print();

return 0;

}

6 0

4 years ago

Choose the 3 correct statements for the code below.

Nookie1986 [14]

Answer:

True

False

True

False

True

Explanation:

So I'll go through each statement and explain why or why not they're correct.

An object of the ActivationLayer class has a name attribute. So because ActivationLayer is inheriting the BaseLayer and it's calling super().__int__("Activation") it's going to call the BaseLayer.__init__ thus setting a name attribute equal to "Activation" for any ActivationLayer object that is initalized. So this is true

An object of the BaseLayer class has a size attribute. While it is true that FC layer is inheriting from BaseLayer and it has a size attribute, this does nothing to change the BaseLayer class. So any object initialized to a BaseLayer object will only have the instance attribute "self.name". So this is false

print(FCLayer(42)) prints FullyConnectedLayer. So whenever you print an object, it tries to convert the object to a string using the __str__ magic method, but if that wasn't defined it then tries the __repr__ method, which the FCLayer class technically doesn't define, but it inherits it from the BaseLayer class. And since whenever you define an FCLayer object it calls super().__init__ with "FullyConnected", which will then be assigned to the instance variable self.name, it will print "FullyConnectedLayer". So this is true

When creating an object of the ActivationLayer class, the size argument must be given. This is true, because the size is a parameter of the __init__ method of ActivationLayer, it is not an optional parameter, and is something that must be passed otherwise an error will be raised. So this is false

When creating an object of the BaseLayer class, the name argument must be given. This is not true, because name is a default argument. This means if you do not pass an argument for name, then name will equal an empty string

4 0

2 years ago

Inheritance enables an object, called a _____, to derive one or more of its attributes from a parent.

jarptica [38.1K]

Answer:

The answer is C.) child

I hope this helps! ^-^

6 0

2 years ago

Select all that apply. Two physical things you can do to demonstrate you are paying attention to a speaker are _____ and _____.

omeli [17]

B and d ............