The 0.25 volume in liters of 1.0 M 
solution is required to provide 0.5 moles of 
(aq).
Calculation,
The Potassium carbonate dissolves as follows:
→ 
The mole ratio is 1: 2
It means, the 1 mole required to form 2 mole of (aq).
To provide 0.5 mole of (aq) = 1 mole ×0.5 mole /2 mole required by .
To provide 0.5 mole of (aq) ,0.25 mole required by .
The morality of = 1 M = number of moles / volume in lit
The morality of = 1 M = 0.25 mole/ volume in lit
Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit
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Most chemical elements are solid at room temperature. Some elements exist as gases but only two elements, mercury (Hg) and bromine (Br) are liquids at room temperature (approx 25oC). Hope this helped you!
Answer:its mercury i think!!!!!
Explanation:
Answer: D=4.35g/L
Explanation:
The formula for density is 
. M is mass in grams and V is volume in liters.
Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.
Ideal Gas Law: PV=nRT
Now that we have moles, we can use molar mass of chlorine gas to find grams.
With our grams, we can find our density.
We need correct significant figures so our density is:
This is asking for the absolute humidity. So if the relative humidity is 65 % and the air temperature is 30 then we need to have in mind the barometric pressure which will be 760. The humidity in the air will be 0.020 kg/m3. In order to know this we calculate it eith the mass of water vapour in a unit volume of air. This is a measure of the actual water vapour content of the air. the for mula would go like this: AH = Mv / V.
