Question

How much heat is absorbed by a 26g iron skillet when its temperature rises from 13oC to 26oC?

Answer 1

Answer:- 152.1 J

Solution:-  This type of problems are solved by using the formula:

$q=mc\Delta T$

where, q is the heat energy, m is the mass, c is specific heat and $\Delta T$ is change in temperature.

mass of iron is given as 26 g. temperature is changing from 13 degree C to 26 degree C.

So, $\Delta T$ = 26 - 13 = 13 degree C

specific heat for iron is 0.450 Joule per gram per degree C.

let's plug in the values in the formula and do calculations for q.

$q=26g*\frac{0.450J}{g.^0C}*13^0C$

q = 152.1 J

So, 152.1 J of heat is absorbed by the iron skillet.