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kirill [66]
3 years ago
9

How much heat is absorbed by a 26g iron skillet when its temperature rises from 13oC to 26oC?

Chemistry
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:- 152.1 J

Solution:-  This type of problems are solved by using the formula:

q=mc\Delta T

where, q is the heat energy, m is the mass, c is specific heat and \Delta T is change in temperature.

mass of iron is given as 26 g. temperature is changing from 13 degree C to 26 degree C.

So, \Delta T = 26 - 13 = 13 degree C

specific heat for iron is 0.450 Joule per gram per degree C.

let's plug in the values in the formula and do calculations for q.

q=26g*\frac{0.450J}{g.^0C}*13^0C

q = 152.1 J

So, 152.1 J of heat is absorbed by the iron skillet.

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3.0 cm x 4.0 cm x 1.0 cm<br><br>[?]cm^3​
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Explanation:

<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>you</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>these</em><em> </em><em>all</em><em> </em><em>right</em><em>,</em>

<em>you</em><em> </em><em>can</em><em> </em><em>simply</em><em> </em><em>multiply</em><em> </em><em>it</em><em> </em><em>,</em>

<em>=</em><em>3</em><em>cm</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>cm</em><em> </em><em>×</em><em> </em><em>1</em><em>cm</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>2</em><em>×</em><em>1</em><em>cm</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>1</em><em>2</em><em>×</em><em>1</em><em>=</em><em>1</em><em>2</em><em>)</em>

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