True, forces do change the motion of an object
Answer:
C) C₆H₁₂O₆.
Explanation:
- We can determine the molecular formula by calculating the molecular mass of different choices.
Molecular mass = ∑(no. of atoms * atomic mass).
A) CH₂O:
molecular mass = atomic mass of C + 2*atomic mass of H + atomic mass of O = (12.0 g/mol) + (2 * 1.0 g/mol) + (16.0 g/mol) = 30.0 g/mol.
B) C₃H₈O₃:
molecular mass = 3(atomic mass of C) + 8(atomic mass of H) + 3(atomic mass of O) = 3(12.0 g/mol) + 8(1.0 g/mol) + 3(16.0 g/mol) = 92.0 g/mol.
C) C₆H₁₂O₆:
molecular mass = 6(atomic mass of C) + 12(atomic mass of H) + 6(atomic mass of O) = 6(12.0 g/mol) + 12(1.0 g/mol) + 6(16.0 g/mol) = 180.0 g/mol.
D) C₈H₁₆O₈:
molecular mass = 8(atomic mass of C) + 16(atomic mass of H) + 8(atomic mass of O) = 8(12.0 g/mol) + 16(1.0 g/mol) + 8(16.0 g/mol) = 240.0 g/mol.
<em>So, the right choice is: C) C₆H₁₂O₆.</em>
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Answer:
the amount present 8 hours ago is Ao = 93.338 g
Explanation:
the radioactive decay is given by
A = Ao * 2^(- t/T)
where T = half-life of the substance , t= time , A= amount of substance at time t , Ao= amount of substance at time 0
therefore at t=8 hours , A=16.5 gr
Ao = A*2^(t/T) = 16.5 g * 2^(8 hours/3.20 hours) = 93.338 g
Ao = 93.338 g
Answer:
is a mutiply choice answer just to be specific
Explanation:
First you need to find out the Limiting reactant (LR). convert both reactants to the same thing. Check that the chemical equation is balanced. Now use stoichiometr and remember at moles, multiply: need moles, divide2 g / 42g/mol= 0.0477 mol propane mass propane/ Molar Mass propane = moles propane4 g / 32 g/mol= 0.125 mol oxygen X (1 mol/ 5 mol) = 0.025 mol propane oxygen is the LRmass O2 / MM O2 X (mol propane / mol O2)0.025 mol X (3 mol / 1 mol ) = .075 mol CO20.075 mol X (12 + 2*16) g /mol = 3.6 g CO2 In one step:2 g / 42g/mol X (3 mol / 1 mol ) X 48 g/mol = 6.86 g CO24 g / 32 g/mol X (3 mol / 5 mol ) X 48 g/mol = 3.6 g CO2mass/ MM X coefficient ratio X MM (new)
