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Anni [7]
3 years ago
8

Which is true about sugar dissolving in water?

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
<span>The correct answer is "Sugar is the solute and water is the solvent". Why? Sugar can be dissolved by water itself, especially in hot water, which is why water is considered to be a solvent, while sugar is considered to be a solute because it can be dissolved.</span>
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I need help with this ASAP PLEASE
Artemon [7]

439.3 g CO2

Explanation:

First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:

3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)

= 9.981 mol CO2

Use the molar mass of CO2 to determine the # of grams of CO2:

9.981 mol CO2 x (44.01 g CO2/1 mol CO2)

= 439.3 g CO2

5 0
2 years ago
In the reaction of chlorine with calcium, explain which atom is oxidized.
romanna [79]

Answer:

The atom is oxidized is Ca.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • The oxidation process is the process in which electrons are lost and produce positively charged ions.
  • The reduction process is the process in which electrons is gained and negatively charge ions are produced.

  • In the reaction of chlorine with calcium:

<em>Ca + Cl₂ → CaCl₂,</em>

Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).

Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).

5 0
3 years ago
Which phase change in an example of an exothermic process?
photoshop1234 [79]
C. liquid to solid  i hope this helps

5 0
3 years ago
Read 2 more answers
It is not possible for global warming to have any positive side effects. Please select the best answer from the choices provided
TiliK225 [7]

False. For example, changing climates will mean that some areas that experience harsh weather will soon being to experience milder weather. :)

8 0
3 years ago
Read 2 more answers
One application of Hess's Law (which works for ΔH, ΔS, and ΔG) is calculating the overall energy of a reaction using standard en
VikaD [51]

Answer:

The standard change in free energy for the reaction =  - 437.5 kj/mole

Explanation:

The standard change in free energy for the reaction:

                              4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)

Given that   ΔGf(KClO3(s)) = -290.9 kJ/mol;

                    ΔGf(KClO4(s)) = -300.4 kJ/mol;

                    ΔGf(KCl(s)) = -409 kJ/mol

According to Hess's law

ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)

               ⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}

                            = - 901.2 - 409 + 872.7

                            =  - 437.5 kj/mole

3 0
3 years ago
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