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USPshnik [31]
3 years ago
14

How much would $500 invested at 6% interest compounded monthly be worth after 5 years? Round your answer to the nearest cent. A(

t)=P(1+r/n)^nt
Mathematics
2 answers:
sergeinik [125]3 years ago
6 0
Please enclose the "nt" inside parentheses:  <span>A(t)=P(1+r/n)^(nt).

Then:  A = $500*(1+0.06/12)^(5*12) = $641.68</span>
horrorfan [7]3 years ago
3 0

Answer:

<h2>$674.42.</h2>

Step-by-step explanation:

Givens

  • The principal of the investment is $500.
  • The interest rate compounded monthly is %6 or 0.06.
  • The time invested is 5 years.

To solve these type of problems, we need to recur to Interest Compound Formula, which is

A(t)=P(1+\frac{r}{n} )^{nt}

Where A is the total amount of money after the time compounded, P is the principal, r is the interest rate, n is the number of compounded periods in one year and r is time in years.

So,

P=500\\r=0.06\\n=12\\t=5

If the problem states that the interest is compounded monthly, then there are gonna be 12 compounded periods in one year. Replacing all these values, we have

A(t)=P(1+\frac{r}{n} )^{nt}\\A(t)=500(1+\frac{0.06}{12} )^{12(5)}\\ A(t)=500(1.005)^{60}= 674.42

Therefore, the total amount of money after 5 years is $674.42.

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The difference between the rate of change of B and the rate of change of A is 15.

<h3>How to get the difference in the rates of change?</h3>

First, we need to get the two rates of change.

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You mean 56.23×10^4?

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