Abigail plays a game in which she spins a spinner over and over again. The spinner has 4 equally sized sections labeled 1 throug
1 answer:
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Answer:
a. 0.9931
b. 0.3423
c. 0.3907
d. 0.2670
e. 3.15
f. 1.0796
Step-by-step explanation:
The probability of the variable that said the number of left-handed people follow a Binomial distribution, so the probability is:
nCx is calculated as:
Where x is the number of left-handed people, n is the number of people selected at random and p is the probability that a person is left--handed. So P(x) is:
Then the probabilities P(0), P(1), P(2), P(3), P(4) and P(5) are:
Then, the probability P(x≥1) that there are some lefties among the 5 people is:
P(x≥1) = P(1) + P(2) + P(3) + P(4) + P(5)
P(x≥1) = 0.0590 + 0.2011 + 0.3423 + 0.2914 + 0.0993 = 0.9931
The probability P(3) that there are exactly 3 lefties in the group is:
P(3) = 0.3423
The probability P(x≥4) that there are at least 4 lefties in the group is:
P(x≥4) = P(4) + P(5) = 0.2914 + 0.0993 = 0.3907
The probability P(x≤2) that there are no more than 2 lefties in the group is:
P(x≤2) = P(0) + P(1) + P(2) = 0.0069 + 0.0590 + 0.2011 = 0.2670
On the other hand, the expected value E(x) and standard deviation S(x) of the variable that follows a binomial distribution is:
It’s 182 my work is in the picture
Answer:
0.966
Step-by-step explanation:
Given that:
Probability of DVD player breaking down before the warranty expires = 0.034
To find:
The probability that the player will not break down before the warranty expires = ?
Solution:
Here, The two events are:
1. The DVD player breaks down before the warranty gets expired.
2. The DVD player breaks down after the warranty gets expired
In other words, the 2nd event can be stated as:
The DVD does not break down before the warranty gets expired.
The two events here, have nothing in common i.e. they are mutually exclusive events.
So, Sum of their probabilities will be equal to 1.