Let r be a radius of a given circle and α be an angle, that corresponds to a sector.
The circle area is
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
and denote the sector area as
![A_1](https://tex.z-dn.net/?f=A_1)
.
Then
![\dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}](https://tex.z-dn.net/?f=%20%5Cdfrac%7BA_1%7D%7BA%7D%3D%20%5Cdfrac%7B%5Calpha%7D%7B2%5Cpi%7D%20)
(the ratio between area is the same as the ratio between coresponding angles).
![A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}](https://tex.z-dn.net/?f=A_1%3D%5Cdfrac%7B%5Calpha%7D%7B2%5Cpi%7D%20%5Ccdot%20A%3D%5Cdfrac%7B%5Calpha%7D%7B2%5Cpi%7D%20%5Ccdot%20%5Cpi%20r%5E2%3D%20%5Cdfrac%7Br%5E2%5Calpha%7D%7B2%7D%20)
.
Answer:
factor of 6 and 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
U still in school
The answer will come out to 30.2
Answer:
A) 2k+4
Step-by-step explanation:
To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.
To start, we will cross multiply. If we have a/b=c/d, then ad=bc
We can perform the same calculation here,
6/x=3/(k+2)
6(k+2)=3x
Divide both sides by 3
2(k+2)=x
x=2k+4