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2 years ago

Pls help i dunno what to do with these problems

Mathematics

2 answers:

Mariulka [41]2 years ago

8 0

I Think it’s D sorry if I’m wrong yo

Evgesh-ka [11]2 years ago

3 0

Answer: D

Step-by-step explanation:

I've done this

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6.<br> A. y=-13x1<br> or B. y = 1-3xl

IrinaVladis [17]

Answer: B

Step-by-step explanation

6 0

3 years ago

Need help please don't know this

4vir4ik [10]

Answer:

x = -3

Step-by-step explanation:

The graph is symmetrical about the vertical line through its vertex:

x = -3

8 0

2 years ago

The larger of two numbers is 4 more than 2 times the smaller number. If the sum of the two numbers is 28, what is the larger num

Musya8 [376]

Answer:

The larger number is 20.

Step-by-step explanation:

Let x and y be the two numbers.

y = 2x + 4

x + y = 28

So x + 2x + 4 = 28

3x = 24

x = 8

y = 20

3 0

3 years ago

If a figure is a triangle, then it has three sides.

stellarik [79]

This answer is true

3 0

3 years ago

Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of

sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error M is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

52% of Independents in the sample opposed the public option.

This means that $p = 0.52$

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when $M = 0.01$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}$

$0.01\sqrt{n} = 0.8218$

$\sqrt{n} = \frac{0.8218}{0.01}$

$\sqrt{n} = 82.18$

$\sqrt{n}^{2} = (82.18)^{2}$

$n = 6754.2$

A sample size of 6755 or higher would be appropriate.

3 0

3 years ago