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Sliva [168]
2 years ago
13

Please help!!!!!!!!!!

Mathematics
2 answers:
BigorU [14]2 years ago
4 0

Answer:

A

Step-by-step explanation:

5,12,13 is a right triangle

zzz [600]2 years ago
4 0

Answer:

answer is b

Step-by-step explanation:

i did a test on it

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Is the algebra, if so what type?
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There are 5 cocoa pods in a bag.
Virty [35]

Answer:

416 g

Step-by-step explanation:

The mean is calculated as

mean = \frac{sum}{count} , then

\frac{sum}{5} = 398 ( multiply both sides by 5 )

sum of 5 pods = 1990 g

let x be the weight of the sixth pod , then

\frac{1990+x}{6} = 401 ( multiply both sides by 6 )

1990 + x = 2406 ( subtract 1990 from both sides )

x = 416

That is the weight of the sixth pod is 416 g

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Suppose two variables are positively correlated. Does the response variable increase or decrease as the explanatory variable inc
matrenka [14]

Answer:

Option A

Step-by-step explanation:

Positive correlation describes a relationship between two variables where both variables move in the same direction. In this case, the response variable will increase as the explanatory variable increases.

3 0
3 years ago
Family drives 4 1/2 miles in 1/10 of an hour. What is their rate of speed in miles per hour?
GarryVolchara [31]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
Which summation formula represents the series below? 1 + 2 + 6 + 24
krek1111 [17]

Question:

Which summation formula represents the series below? 1 + 2 + 6 + 24

(a) \sum_{n=2}^{5}(n-1) !

(b) \sum_{n=0}^{3} n !

(c) \sum_{n=1}^{4}(n+1) !

(d) \sum_{n=2}^{5} n !

Answer:

Option a: \sum_{n=2}^{5}(n-1) ! is the correct answer.

Explanation:

Option a: \sum_{n=2}^{5}(n-1) !

By substituting the values of n and expanding the summation, we have,

(2-1) !+(3-1) !+(4-1) !+(5-1) !

Subtracting, we have,

1 !+2!+3 !+4 !

Expanding the factorial,

1+(2*1)+(3*2*1)+(4*3*2*1)

Simplifying, we get,

1+2+6+24

Thus, the summation \sum_{n=2}^{5}(n-1) ! represents the series 1+2+6+24

Hence, Option a is the correct answer.

Option b: \sum_{n=0}^{3} n !

By substituting the values of n and expanding the summation, we have,

0!+1!+2!+3!

Expanding the factorial,

0+1+(2*1)+(3*2*1)

Simplifying, we get,

0+1+2+6

Thus, the summation \sum_{n=0}^{3} n ! does not represents the series 1+2+6+24

Hence, Option b is not the correct answer.

Option c: \sum_{n=1}^{4}(n+1) !

By substituting the values of n and expanding the summation, we have,

(1+1) !+(2+1) !+(3+1) !+(4+1) !

Adding, we have,

2!+3!+4!+5!

Expanding the factorial,

(2*1)+(3*2*1)+(4*3*2*1)+(5*4*3*2*1)

Simplifying, we get,

2+6+24+120

Thus, the summation \sum_{n=1}^{4}(n+1) ! does not represents the series 1+2+6+24

Hence, Option c is not the correct answer.

Option d: \sum_{n=2}^{5} n !

By substituting the values of n and expanding the summation, we have,

2!+3!+4!+5!

Expanding the factorial,

(2*1)+(3*2*1)+(4*3*2*1)+(5*4*3*2*1)

Simplifying, we get,

2+6+24+120

Thus, the summation \sum_{n=2}^{5} n ! does not represents the series 1+2+6+24

Hence, Option d is not the correct answer.

Hence, the correct answer is Option a: \sum_{n=2}^{5}(n-1) !

6 0
4 years ago
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