It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.
In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x
2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y
now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5
now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0
and now we have solved the problem. x=0 and y=-5
Answer:
a number plus 14
fourteen more than a number
a number increased by 14
Step-by-step explanation:
The phrases which can be represented by the algebraic expression x + 14 are
Let x = the unknown number
a number plus 14
= x + 14
fourteen more than a number
= x + 14
a number increased by 14
x + 14
4) In triangle, angle opposite to perpendicular is 90-60 = 30
So, tan Ф = P/B
tan 30 = a / 6
1/√3 = a/6
a = 6/√3
a = 2√3
Now, cosФ = B/H
cos 30 = 6/b
√3/2 = 6/b
b = 6*2/√3
b = 12/√3
b = 4√3
In short, Your Answer would be a = 2√3 and b = 4√3
Hope this helps!
