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never [62]
2 years ago
8

What is 1/4 divided by 1 and 3/4?

Mathematics
1 answer:
natta225 [31]2 years ago
6 0

Answer:

1/4 / 1 3/4 = 1/7

Step-by-step explanation:

Calculation steps:

1/4 ÷ 7/4 = 1/4 x 4/7 = 4/28 = 4 ÷ 4 and 28 ÷ 4 = 1/7 simplified

Hope it helps:)

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A total of $20,000 is to be invested, some in bonds and some in certificates of deposit (CDs). If the amount invested in bonds i
Brilliant_brown [7]

Answer:

$8,500 in CDs; $11,500 in bonds

Step-by-step explanation:

Let c = amount invested in CDs.

Let b = amount invested in bonds.

"A total of $20,000 is to be invested, some in bonds and some in certificates of deposit (CDs)."

From the total investment, we get this equation.

c + b = 20000

"If the amount invested in bonds is to exceed that in CDs by $3000"

From the details of the amounts, we get this equation.

b = c + 3000

We have a system of equations in two unknowns.

c + b = 20000  Eq. 1

b = c + 3000  Eq. 2

Since Eq. 2 is already solved for b, we will use the substitution method to solve the system of equations.

Substitute b in Eq. 1 with c + 3000.

c + c + 3000 = 20000

2c + 3000 = 20000

2c = 17000

c = 8500

Now substitute c = 8500 in Eq. 2 and solve for b.

b = c + 3000

b = 8500 + 3000

b = 11500

Answer: $8,500 in CDs; $11,500 in bonds

6 0
3 years ago
What are the first 10 prime numbers and How
Anna [14]
2, 3, 5, 7, 11, 13, 17, 19, 23, 29

A prime number is a number that is only divisible by 1 and itself

3 0
3 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
Helppp Plssssss Asap!!<br><br>Thanks
sdas [7]

Answer:

Its B im pretty sure

Step-by-step explanation:


4 0
3 years ago
Give an example of how the zero product property applies to solving quadratic equations
mestny [16]

Answer:

How the zero product property applies to solving quadratic equations?

The zero product property states that if the product of two quantities is zero, then one or both of the quantities must be zero. ... When you factor, you turn a quadratic expression into a product. If you have a quadratic expression equal to zero, you can factor it and then use the zero product property to solve.

Step-by-step explanation:


8 0
3 years ago
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