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never [62]
2 years ago
8

What is 1/4 divided by 1 and 3/4?

Mathematics
1 answer:
natta225 [31]2 years ago
6 0

Answer:

1/4 / 1 3/4 = 1/7

Step-by-step explanation:

Calculation steps:

1/4 ÷ 7/4 = 1/4 x 4/7 = 4/28 = 4 ÷ 4 and 28 ÷ 4 = 1/7 simplified

Hope it helps:)

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How many weeks when the amount of money Hannah owed her friend was 18$
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I believe it’s 3.5 but I could totally be wrong I’m not much help at all
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2 years ago
Write an equation of the circle with center (5, -7) and radius 9.
vagabundo [1.1K]

Answer:

(x - 5)² + (y + 7)² = 81

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (5, - 7) and r = 9, thus

(x - 5)² + (y - (- 7))² = 9², that is

(x - 5)² + (y + 7)² = 81 ← equation of circle

6 0
3 years ago
Someone please explain how to do this problem? :)<br><br> Factor completely 2c5 + 44c4 + 242c3.
frez [133]
<span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span>=<span><span><span>2<span>c3</span></span><span>(<span>c+11</span>)</span></span><span>(<span>c+11</span><span>)</span></span></span></span>
8 0
3 years ago
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I have 10and4/5 of cake batter to split among 18 cupcakes. How many cups of batter will I use for each cupcake
Verdich [7]
Information given to us:
10 4/5 total cake batter
18 cupcakes
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5 0
3 years ago
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Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².​
Liula [17]

Step-by-step explanation:

Let y(x)=f(x)g(x)h(x) where

f(x) = x^4

g(x)= (1 -2x^5)^6

h(x)= (5 - 8x^3)^2

so that

y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2

Recall that the derivative of the product of functions is

y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)

so taking the derivatives of the individual functions, we get

f'(x) = 4x^3

g'(x) = 6(1 - 2x^5)^5(-10x^4)

h'(x) = 2(5 - 8x^3)(-24x^2)

So the derivative of y(x) is given by

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 +  x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 +  x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)

or

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)

3 0
2 years ago
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