2 years ago

The law of cosines is a² + b² - 2abcosC = c². find the value of 2abcosC

Mathematics

2 answers:

taurus [48]2 years ago

7 0

$\bf a^2+b^2-(2ab)cos(C)=c^2\implies a^2+b^2-c^2=(2ab)cos(C)$

Elina [12.6K]2 years ago

3 0

Answer:

We need a diagram please

Step-by-step explanation:

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3 years ago

When f(x) = x2+9 and g(x) = x-9, find f(x)-g(x).

ohaa [14]

Answer:

$\huge{ \boxed{ \sf{ {x}^{2} - x + 18}}}$

Step-by-step explanation:

$\underline{ \text{Given}}:$

$\sf{f(x) = {x}^{2} +9 \: and \: g(x) = x-9}$

$\underline{ \text{To \: find}} : \sf{ \: f(x) \: - \: g(x)}$

Put the values:

$\mapsto{ \sf{ {x}^{2} + 9 - ( x - 9)}}$

While subtracting , sign of each term of the second expression changes.

$\mapsto{ \sf{ {x}^{2} + 9 - x + 9}}$

Add the numbers : 9 and 9

$\mapsto{ \boxed{ \sf{{x}^{2} - x + 18}}}$

Hope I helped!

Best regards! :D

~ $\text{TheAnimeGirl}$

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strojnjashka [21]

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