Can anyone help me with this question it would be good if you can show me the graph

Mathematics

1 answer:

natta225 [31]2 years ago

8 0

See image for work and answer

You might be interested in

I neeeeeeeeeed heeeeelp

ruslelena [56]

Answer:

F i think

Step-by-step explanation:

6 0

4 years ago

What is the probability of rolling a number greater than 4 on a fair number cube (dice)? (Simplify to lowest terms)

Reptile [31]

Answer:

1/3

Step-by-step explanation:

there are 2 numbers greater than 4 on dice and there are 6 numbers on a die

3 0

3 years ago

Find M ABC if the line BD bisects ABC and given m ABD = 5x and m DBC = 3x + 10

stira [4]

Answer:

The Answer: 50°

Step-by-step explanation:

3 0

3 years ago

If you horizontally stretch the quadratic parent function, f(x) = x2, by a factor of 4, what is the equation of the new function

navik [9.2K]

Please write x^2, not x2.

If you stretch the graph of y=x^2 vertically by a factor of 4, the resulting graph represents the quadratic function y = 4x^2. It's still a parabola, but appears to be thinner.

This particular question is about horizontal stretching, however. Stretching the graph horizontally by a factor of 4 results in the new function g(x) = (x/4)^2. Try graphing x^2 and also (x/4)^2 on the same set of axes to observe this phenomenon.

3 0

3 years ago

Read 2 more answers

Which of the following is equivalent to 6x 2 + x - 12 ?

bagirrra123 [75]

$6x^2+x-12=6x^2-9x+8x-12=3x(2x-3)+4(2x-3)\\\\=(2x-3)(3x+4)\\\\other\ method:\\\\6x^2+x-12\\a=6;\ b=1;\ c=-12\\\Delta=b^2-4ac\to\Delta=1^2-4\cdot6\cdot(-12)=1+288=289\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{289}=17$

$x_1=\frac{-1-17}{2\cdot6}=\frac{-18}{12}=-\frac{3}{2};\ x_2=\frac{-1+17}{2\cdot6}=\frac{16}{12}=\frac{4}{3}\\\\6x^2+x-12=6(x+\frac{3}{2})(x-\frac{4}{3})=2\cdot3(x+\frac{3}{2})(x-\frac{4}{3})\\\\=2(x+\frac{3}{2})\cdot3(x-\frac{4}{3})=(2x+3)(3x-4)$

4 0

3 years ago