-2 -13.8x = -8 -6x -1
First, I distributed the negative 1 that was outside of the parentheses to the positive 6x and the positive 1.
-2 -13.8x = -9 -6x
Then I added the negative 8 to the negative 1 which equals negative 9.
-2 -13.8x +6x = -9 -6x +6x
After that I used the addition property and added a positive 6x to both sides.
-2 -7.8x = -9
Then simplifying.
+2 -2 -7.8x = -9 +2
After simplifying, I used the addition property again, adding a positive 2 to both sides.
-7.8x = -7
Simplified.
-7.8x (-1) = -7 (-1)
Then I multiplied both sides by with a negative 1 since the variable cannot be a negative.
7.8x = 7
Simplified
(1/7.8) 7.8x = (1/7.8) 7
Then, to isolate the veriable, I multiplied 1/7.8 to both sides.
x = 1.11428571429
The answer !
I hope this helped !
Answer:
C.$0.15 I TOOK IT ON STUDY ISLAND
Step-by-step explanation:
First, you want to find an exact point on the graph. What I mean by this is you want to go somewhere on the graph where the line goes through an exact y and x value.
Second, you want to figure out where this x and y value are. Where the graph first goes through two points is at (20, 3).
Third, you want to figure out what the 20 and the 3 mean. 20 is the number of messages and 3 is the dollar amount.
Finally, to calculate the amount of money per message, you divide the dollar amount (3) by the number of messages (20). So, you have 3/20. After this, simplify 3/20 to get 0.15, or 15 cents per message.
Answer:
15 liters
Step-by-step explanation:
Given:
We need 5 liters of Yoda soda for 12 guest.
To find:
If we have 36 guest how many liters of Yoda soda we need.
Solution:
<u>By unitary method:</u>
For 12 guests, we need liters of Yoda soda = 5
For 1 guest, we need liters of Yoda soda = 
For 36 guests, we need liters of Yoda soda = 
Therefore, we need 15 liters of Yoda soda for 36 guests.
Answer 2/5. It says there are 5 people and 3 of them have done their hw and 2 have not cause 5-3=2.
I can't solve it but you can enter the equation into www.quickmath.com and it will give you the answer. Hope it helps.
