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castortr0y [4]
2 years ago
7

Natural Selection quiz answer: Describe ways the simulation was limited in Challenge 2 (limited food for bunnies) and what are s

ome modifications that can be made to the simulation so that it more closely resembles real life?
Chemistry
2 answers:
Katena32 [7]2 years ago
7 0
There isn’t really a question here; that’s reliant on the simulation you used. Unless you’re generally speaking, then unfortunately, you’re on your own with this one.
xz_007 [3.2K]2 years ago
4 0

Answer:

more predators, more food options, and more climates

Explanation:

sorry I couldn't answer the whole essay question.

You might be interested in
What is the enthalpy for reaction 1 reversed? reaction 1 reversed: 2co2 + 3h2o→c2h5oh + 3o2 express your answer numerically in k
Rama09 [41]

Answer: The enthalpy of the given reaction is 1234.8kJ/mol.

Explanation: Enthalpy change of the reaction is the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}

For the given reaction:

2CO_2(g)+3H_2O(g)\rightarrow C_2H_5OH(l)+3O_2(g)

H_f_{(CO_2)}=-393.5kJ/mol

H_f_{(H_2O)}=-241.8kJ/mol

H_f_{(C_2H_5OH)}=-277.6kJ/mol

H_f_{(O_2)}=0kJ/mol

\Delta H_{rxn}=\Delta H_f_{(C_2H_5OH)}+3\Delta H_f_{(O_2)}-[2\Delta H_f_{(CO_2)}+3\Delta H_f_{(H_2O)}]

Putting values in above equation, we get:

\Delta H_{rxn}=[-277.6+3(0)]-[2(-393.5)+3(-241.8)]kJ/mol

\Delta H_{rxn}=1234.8kJ/mol

7 0
3 years ago
2. What is a product?
zysi [14]

Answer:an article or substance that is manufactured or refined for sale.

"food products"

2.

a thing or person that is the result of an action or process.

"her perpetual suntan was the product of a solarium"

Explanation:

6 0
3 years ago
Read 2 more answers
If elasticity increases, does the speed of sound increase?
shtirl [24]
Sound increases my the sound waves
4 0
3 years ago
Read 2 more answers
A 544 mg of a mixture of fluorene and benzoic acid was weighed out and subjected to an extraction and recrystallization. After t
butalik [34]

<u>Answer:</u> The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.

<u>Explanation:</u>

We are given:

Mass of mixture = 544 mg

Mass of fluorene after purification = 1.80\times 10^2mg=180mg

Mass of benzoic acid after purification = 196 mg

To calculate the percentage composition of a substance in a mixture, we use the equation:

\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

<u>For fluorene:</u>

\%\text{ composition of fluorene}=\frac{180}{544}\times 100=33.08\%

Hence, the percent composition of fluorene is 33.08 %

<u>For benzoic acid:</u>

\%\text{ composition of benzoic acid}=\frac{196}{544}\times 100=36.03\%

Hence, the percent composition of benzoic acid is 36.03 %

5 0
4 years ago
How many moles are in a 12.0 g sample of NiC12
Nady [450]

Answer:

0.17 moles

Explanation:

In the elements of the periodic table, the atomic mass = molar mass. <u>Ex:</u> Atomic mass of Carbon is 12.01 amu which means molar mass of Carbon is also 12.01g/mol.

In order to find the # of moles in a 12 g sample of NiC-12, we will need to multiply the number of each atom by its molar mass and then add the masses of both Nickel and C-12 found in the periodic table:

  • Molar Mass of Ni (Nickel): 58.69 g/mol
  • Molar Mass of C (Carbon): 12.01 g/mol

Since there's just one atom of both Carbon and Nickel, we just add up the masses to find the molar mass of the whole compound of NiC-12.

  • 58.69 g/mol of Nickel + 12.01 g/mol of Carbon = 70.7 g/mol of NiC-12

There's 12g of NiC-12, which is less than the molar mass of NiC-12, so the number of moles should be less than 1. In order to find the # of moles in NiC-12, we need to do some dimensional analysis:

  • 12g NiC-12 (1 mol of NiC-12/70.7g NiC-12) = 0.17 mol of NiC-12
  • The grams cancel, leaving us with moles of NiC-12, so the answer is 0.17 moles of NiC-12 in a 12 g sample.

<em>P.S. C-12 or C12 just means that the Carbon atom has an atomic mass of 12amu and a molar mass of 12g/mol, or just regular carbon.</em>

5 0
3 years ago
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