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siniylev [52]
3 years ago
9

I need help plz help me

Chemistry
1 answer:
zaharov [31]3 years ago
5 0

Answer:

A

Explanation:

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Generally the ionization potential in a period increases, but there are some exceptions. The one which is not an exception is
Sunny_sXe [5.5K]

Answer:

Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception

4 0
2 years ago
When co2 levels are low and o2 levels are high, rubisco adds an o2 molecule to rubp. what are the consequences of this reaction?
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Rubisco is an important enzyme that helps in making lifeless carbon of carbon dioxide into organic molecules. Rubisco takes carbon dioxide and attaches it to ribulose bisphosphate, a short sugar chain with five carbon atoms that has rubp as its shortcut. Rubisco then clips the lengthened chain into to polyglycerate pices, which are pretty flexible molecules and are also used in the feeding of the plant. Most of it is used in the photosynthesis pathway, but some of it is used to make sucrose (table sugar) to feed the rest of the plant, or stored away in the form of starch for later use. Hence, rubisco is crucial in the storing of the energy that is created from photosynthesis.


4 0
3 years ago
Based on the following chemical equation how many hydrogen atoms are present in the products side?
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Answer:

the answer is 6

Explanation:

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8 0
2 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
2 years ago
Balance the equation and write the reaction-quotient expression, qc. u(s) + f2(g) ----&gt; uf6(g)
Alona [7]
The equation presented above is that of uranium reacting with fluorine forming uranium fluoride. 

The chemical reaction can be balanced by carefully studying the equation and balancing the number of atoms of each of the element in both sides of the chemical reaction. That is,
 
                  <em>         U(s) + 3F₂(g) --> UF₆(g)</em>
4 0
3 years ago
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