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kati45 [8]
4 years ago
9

Find x. 3х + 4 6x - 2

Mathematics
2 answers:
Naddika [18.5K]4 years ago
6 0
To find X, the answer would be 2
8_murik_8 [283]4 years ago
3 0

Answer:

x=2/27≈0.0740740740740741

Step-by-step explanation:

27x−2=0

Add me on  instagram at skyy.thatdancer

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Suppose Casey Title Company normally charges $300 for services related to selling a house. As part of a summer special, Casey of
g100num [7]

Given :

Casey's company charges , C = $300.

In summer special, Casey offers customers a trade discount of 25%.

To Find :

Charges during summer.

Solution :

Let, x is the amount of charges they take during summer.

Casey offers customers a trade discount of 25%.

x =300(1-\dfrac{25}{100})\\\\x=300(1 - 0.25)\\\\x=300(0.75)\\\\x=\$225

Therefore, amount of charges during summers are $225.

Hence, this is the required solution.

8 0
3 years ago
Find the xx-intercept of each line defined below and compare their values.
alexandr1967 [171]

Answer:

\displaystyle greater\:than \\ Line\:B: [-6, 0] \\ Line\:A: [2, 0]

Step-by-step explanation:

The x-intercept of Line B is already given to you because it is where the graph intersects the x-axis.

Now, to get the x-intercept of Line A, plug 0 in for <em>y</em><em> </em>to get this:

0 = −2x + 4

- 4 - 4

_____________

\displaystyle \frac{-4}{-2} = \frac{-2x}{-2} \\ \\ 2 = x

So, the x-intercept of Line A is \displaystyle [2, 0],and since 2 is greater than −6, <em>greater than</em> would be your answer.

I am joyous to assist you anytime.

5 0
4 years ago
If there is a nonmathematical symbol in the preceding expression, then your browser doesn't have the math symbol font. Please fo
horrorfan [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 g(h(x)) = \sqrt[4]{x^2 + x +5} + 3

b

 h(g(x))  = \sqrt{x}  + 7\sqrt[4]{x} + 17

c

 h(h(x)) =  [x^2 + x + 5 ]^2 + x^2 + x + 10

Step-by-step explanation:

From the question we are told that

    h(x) =  x^2  + x  + 5

and  

    g(x) = \sqrt[4]{x} + 3

Considering first question

Now we are told  g(h(x))

i.e

        g(h(x)) =  [x^2 + x + 5 ]^{\frac{1}{4} } + 3

=>     g(h(x)) = \sqrt[4]{x^2 + x +5} + 3

Considering second  question

   Now we are told  h(g(x))

i.e

    h(g(x)) =  [x^{\frac{1}{4} } + 3]^2 +  x^{\frac{1}{4} } + 3 + 5

=> h(g(x)) =  x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}}  + 8

=>  h(g(x))  = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17

=>  h(g(x))  = \sqrt{x}  + 7\sqrt[4]{x} + 17

Considering third question

         h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] +  5

=>       h(h(x)) =  [x^2 + x + 5 ]^2 + x^2 + x + 10

8 0
4 years ago
491,852 people went to the water park in the month of July . Round this number to the nearest hundred thousand to estimate how m
Vinvika [58]
The 8 round to nearest
hundred
5 0
3 years ago
Read 2 more answers
I want the answer to this question please .
stepan [7]

X=46...she need to get on 6th exam to have an average of 60

6 0
3 years ago
Read 2 more answers
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