Given :
Casey's company charges , C = $300.
In summer special, Casey offers customers a trade discount of 25%.
To Find :
Charges during summer.
Solution :
Let, x is the amount of charges they take during summer.
Casey offers customers a trade discount of 25%.

Therefore, amount of charges during summers are $225.
Hence, this is the required solution.
Answer:
![\displaystyle greater\:than \\ Line\:B: [-6, 0] \\ Line\:A: [2, 0]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20greater%5C%3Athan%20%5C%5C%20Line%5C%3AB%3A%20%5B-6%2C%200%5D%20%5C%5C%20Line%5C%3AA%3A%20%5B2%2C%200%5D)
Step-by-step explanation:
The x-intercept of Line B is already given to you because it is where the graph intersects the x-axis.
Now, to get the x-intercept of Line A, plug 0 in for <em>y</em><em> </em>to get this:
0 = −2x + 4
- 4 - 4
_____________

So, the x-intercept of Line A is
and since 2 is greater than −6, <em>greater than</em> would be your answer.
I am joyous to assist you anytime.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![g(h(x)) = \sqrt[4]{x^2 + x +5} + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%20%2B%20x%20%2B5%7D%20%2B%203)
b
![h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%20%3D%20%5Csqrt%7Bx%7D%20%20%2B%207%5Csqrt%5B4%5D%7Bx%7D%20%2B%2017)
c
![h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10](https://tex.z-dn.net/?f=h%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E2%20%2B%20x%5E2%20%2B%20x%20%2B%2010)
Step-by-step explanation:
From the question we are told that

and
![g(x) = \sqrt[4]{x} + 3](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B4%5D%7Bx%7D%20%2B%203)
Considering first question
Now we are told g(h(x))
i.e
![g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203)
=> ![g(h(x)) = \sqrt[4]{x^2 + x +5} + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%20%2B%20x%20%2B5%7D%20%2B%203)
Considering second question
Now we are told h(g(x))
i.e
![h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%3D%20%20%5Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%5D%5E2%20%2B%20%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%20%2B%205)
=> 
=> 
=> ![h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%20%3D%20%5Csqrt%7Bx%7D%20%20%2B%207%5Csqrt%5B4%5D%7Bx%7D%20%2B%2017)
Considering third question
![h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5](https://tex.z-dn.net/?f=h%28h%28x%29%29%3D%20%5Bx%5E2%20%2B%20x%20%2B%205%5D%5E2%20%2B%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%20%2B%20%205)
=> ![h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10](https://tex.z-dn.net/?f=h%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E2%20%2B%20x%5E2%20%2B%20x%20%2B%2010)
X=46...she need to get on 6th exam to have an average of 60