Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
X= -12 Y=10
Step-by-step explanation:
Answer:
14 and 17
Step-by-step explanation:
x+y=41
y=2x-1
x+(2x-1)=41
3x-1=41
3x=42
x=14
y=2(14)-1=27
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