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Irina-Kira [14]
2 years ago
7

In the EST graph above, what is the required time to complete task A? ​

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
8 0

Answer:

  5 time units

Step-by-step explanation:

The number on the arrow in this graph is the task completion time.

__

The completion time for Task A is 5 time units.

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A number picked at random from the numbers 1 through 15 is prime. This "question" is on my study guide for Unit 6 Probability an
Sphinxa [80]

Solution:

we are given that

A number picked at random from the numbers 1 through 15 is prime.

As we know the number between 1 and 15 which are primes are listed below

2,3,5,7,11,13.

Here total number of favourable outcomes are 6.

The numbers 1 through 15 are as below:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15.

Here total number of possible outcoes are 15.

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime=\frac{6}{15}=\frac{2}{5}=0.40

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime is 0.4

6 0
4 years ago
Read 2 more answers
Round 36.319 to the nearest tenth
vampirchik [111]
36.3 because the digit in the hundredths place is not 5 or greater
3 0
3 years ago
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Which table identifies the one-sided and two-sided limits of function at x = 2?​
Yuliya22 [10]

Answer:

Table 3

Step-by-step explanation:

Check table three;

lim\:_{x\to \:2^-}\:f\left(x\right)=\:4

lim\:_{x\to \:2^+}\:f\left(x\right)=\:1

Since the left hand limit (lim\:_{x\to \:2^-}\:f\left(x\right)) is not equal to the right hand limit (lim\:_{x\to \:2^+}\:f\left(x\right)),  the limit as x approaches to 2 does not exist.

Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2

6 0
3 years ago
I'll give brainiest to the first correct answer
Elanso [62]

Answer: the first one is the answer I think

Step-by-step explanation:

6 0
3 years ago
Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
4 years ago
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