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2 years ago

In the EST graph above, what is the required time to complete task A?

Mathematics

1 answer:

Oksi-84 [34.3K]2 years ago

8 0

Answer:

5 time units

Step-by-step explanation:

The number on the arrow in this graph is the task completion time.

The completion time for Task A is 5 time units.

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I need help please?!!

Rasek [7]

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3 years ago

£2200 is deposited in a bank paying 0.5% simple interest per annum. How much interest will have been paid after 18 years?

seraphim [82]

Answer:

The answer would be £198

principal (p) = 2200

Rate (R) = 0.5%

Time (T) = 18

Interest(I) = ?

Now,

or, Interest. = P×T×R/100

or, Interest = 2200×18×0.5/100

or, Interest = 19800/100

Hence, Interest = 198

4 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

Find the volume of a pyramid with a square base of 6 meters on each side and a height of 27 meters

ASHA 777 [7]

972 meters will be your answer

5 0

2 years ago

Help solve w(5w^3)^-2 / w^-4

Bond [772]

Start with the exponents, 3 and -2, you multiply them together so you get -6 so its w(w^-6)/w^-4 and then you do wx5w^-6 which is 5w^-4 bc im pretty sure you multiply it to 5w and thats 5w squared so you just add it and so it becomes 5w^-4/5w^-4 and you can simplify that

3 0

2 years ago

In the EST graph above, what is the required time to complete task A? ​

In the EST graph above, what is the required time to complete task A?