C=.80n+7 for question a, question d is 6 toppings. I forget how to do an input output graph for b and c, my bad
I believe it is the first one
This follows the base equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
both of the variables are squared, and they're being added--you've got a circle.
Answer:
14q^2−2q+14/3
Step-by-step explanation:
9q^2 - 2/3 (3q - 7) + 5q^2
Use the distributive property to multiply -2/3 by 3q−7.
9q^2 - 2q + 14/3 + 5q^2
Combine 9q^2 and 5q^2 to get 14q^2
14q^2−2q+14/3
Answer:
2520 ways
Step-by-step explanation:
We can solve this problem with 3 combinations:
First the teacher needs to give 3 fruit snacks to 10 students, so we have a combination of 10 choose 3: C(10,3) = 10! / (3! * 7!) = 120
Then, she needs to give 2 teddy grahams to 7 students (3 already got a snack), so a combination of 7 choose 2: C(7,2) = 7! / (2! * 5!) = 21
The, she gives the 5 granola bars to the other 5 students, so a combination of 5 choose 5: C(5,5) = 1.
Now we just need to multiply the combinations to find the result:
C(10,3) * C(7,2) * C(5,5) = 120 * 21 * 1 = 2520 ways
