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o-na [289]
2 years ago
12

A

Mathematics
1 answer:
netineya [11]2 years ago
5 0

1.25 percent of 3000=37.5

37.5 times 4=150

3000-150=2850

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Country Financial, a financial services company, uses surveys of adults age and older to determine if personal financial fitness
Yakvenalex [24]

Complete Question

Country financials, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. In February 2012, a sample of 1000 adults showed 410 indicating that their financial security was more that fair. In Feb 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair.

a

State the hypotheses that can be used to test for a significant difference between the population proportions for the two years.

b

What is the sample proportion indicating that their  financial security was more that fair in 2012?In 2010?

c

Conduct the hypothesis test and compute the p-value.At a .05 level of significance what is your conclusion?

Answer:

a

The null hypothesis is  H_o :  p_1 = p_2

The  alternative hypothesis is   H_a :  p_1  \ne  p_2

b

in 2012  \r  p_1  =0.41

in 2010  \r  p_2  =0.35  

c

The  p-value  is  p-value = 0.0072

The conclusion is

There is  sufficient evidence to conclude that the proportion of those indicating that  financial security is more fair in Feb 2010 is different from the proportion of  those indicating that financial security is more fair in Feb 2012.

Step-by-step explanation:

From the question we are told that

   The  sample size in 2012 is  n_1  =  1000

    The  number that indicated that their finance was more than fail is  k  =  410  

     The  sample  size in 2010  is  n_2  =  900

   The  number that indicated that their finance was more than fail is  u  =  315

     The  level of significance is  \alpha  =  0.05[/ex]The null hypothesis is  [tex]H_o :  p_1 = p_2

The  alternative hypothesis is   H_a :  p_1  \ne  p_2

Generally the sample proportion for  2012 is mathematically represented as

     \r  p_1  =  \frac{k}{n_1}

=>   \r  p_1  =  \frac{410}{1000}

=>   \r  p_1  =0.41

Generally the sample proportion for  2010 is mathematically represented as

      \r  p_2  =  \frac{u}{n_2}

=>   \r  p_2  =  \frac{315}{900}

=>   \r  p_2  =0.35    

Generally the pooled sample proportion is mathematically represented as

      \r p =  \frac{k + u }{n_1 + n_2}

=>     \r p =  \frac{410 + 315 }{1000+ 900}

=>      \r p =  0.3816

Generally the test statistics is mathematically represented as

     z =  \frac{( \r p_1 - \r p_2 ) - 0}{\sqrt{\r p (1 - \r p ) ( \frac{1}{n_1} +\frac{1}{n_2} )}  }

 z =  \frac{( 0.41 -0.35 ) - 0}{\sqrt{0.3816 (1 - 0.3816 ) ( \frac{1}{1000} +\frac{1}{900} )}  }    

 

 z =  \frac{( 0.41 -0.35 ) - 0}{\sqrt{0.3816 (1 - 0.3816 ) ( \frac{1}{1000} +\frac{1}{900} )}  }

   z  =  2.688

Generally the p- value  is mathematically represented as  

      p-value = 2 P(Z >2.688  )

From the z -table  

      P(Z > 2.688) = 0.0036

So  

      p-value = 2 *0.0036

        p-value = 0.0072

So from the p-value  obtained we see that p-value  <  \alpha so we reject the null hypothesis

Thus there is  sufficient evidence to conclude that the proportion of financial security is more fair in Feb 2010 is different from the proportion of financial security is more fair in Feb 2012.

5 0
4 years ago
What is the solution to the following system? 4x+3y-z=-6 6x-y+3z=12 8x+2y+4z=6
andrew-mc [135]

Answer:

Option B is correct.

Step-by-step explanation:

4x+3y-z= -6     eq(1)

6x-y+3z= 12     eq(2)

8x+2y+4z=6    eq(3)

We need to solve these equations and find the value of x, y and z.

Multiply equation 2 with 3 and then add equation 1 and 2

18x -3y +9z = 36

4x +3y -z = -6

_____________

22x + 8z = 30    eq(3)

Multiply equation 2 with 2 and add with equation 3

12x -2y + 6z = 24

8x +2y +4z = 6

____________

20x + 10 z = 30  eq(4)

Multiply equation 3 with 10 and equation 4 with 8 and then subtract

220x + 80z = 300

160x + 80z = 240

-        -            -

_________________

60x = 60

x= 60/60

x= 1

Putting value of x in equation 3

22x + 8z = 30

22(1) + 8z = 30

8z = 30 - 22

8z = 8

z = 8/8

z=1

Putting value of x and z in equation 1

4(1)+3y-(1)=-6

4 + 3y -1 = -6

3 + 3y = -6

3y = -6 -3

3y = -9

y = -3

so, Option B x=1, y=3 and z=1 is correct

8 0
3 years ago
Read 2 more answers
2nd term of (2r-3s)^12
earnstyle [38]

Answer:

1.-12*(2r)^11 * (3s)

= -12*2048*3 r^11 s

= -73728 r^11 s

2.12C1 (2r)¹¹(-3s) = -36(2¹¹)r¹¹s = -73728r¹¹s

3.24 r - 36 s

The second term: -36 s

4.(2r-3s)^12

= (2r)^12 + 12C1 (2r)^11 (-3s)

= 2^12 r^12 + (12) 2^11 r^11 (-3) s

= 4096 r^12 - (12)(3)(2098) r^11 s

= 4096 r^12 - 73,728 r^11 s + .....

-73,728 r^11 s

Step-by-step explanation:

Yan lang po alam ko at nahirapan ako e solved yan hehe pero hope it helps

4 0
3 years ago
Plz help I will thank u and mark u as branilyest
IceJOKER [234]

 number 9 =al you have to do is one and 7 eighths =9 so your sum will be 10 and 7 eighths.

hope this helps;)

MARK ME BRAINLIEST

YOU PROMISED!

8 0
3 years ago
Read 2 more answers
Which of the following objects has the most kinetic energy? A. a car driving on the freeway B. a pumpkin getting carved into a j
taurus [48]
A. A car driving on the freeway. Because it is moving
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8 0
3 years ago
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