Answer:
210 cm²
Step-by-step explanation:
The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.
Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles
✔️Area of the 2 trapezoid bases:
Area = 2(½(a + b)×h)
Where,
a = 7 cm
b = 11 cm
h = 3 cm
Plug in the values
Area = 2(½(7 + 11)×3)
= (18 × 3)
Area of the 2 trapezoid bases = 54 cm²
✔️Area of Rectangle 1:
Length = 6 cm
Width = 3 cm
Area = 6 × 3 = 18 cm²
✔️Area of Rectangle 2:
Length = 7 cm
Width = 6 cm
Area = 7 × 6 = 42 cm²
✔️Area of Rectangle 3:
Length = 6 cm
Width = 5 cm
Area = 6 × 5 = 30 cm²
✔️Area of Rectangle 4:
Length = 11 cm
Width = 6 cm
Area = 11 × 6 = 66 cm²
✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²
Solution :
Given :
Sample mean, 
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with 
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about 
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
Answer:
an = (1 + 2·(n - 1))/2^(n - 1) = 2^(1 - n)·(2·n - 1)
sn = 6 - 2·0.5^n·(2·n + 3)
So...we can write eqn as
40x = 50(x-1)
so. -10x=-50
so. x=5
therefore .... the distance of 40 lb will be 5 ft ...answer !!!
Answer:
6 5/6
Step-by-step explanation:
8
- 1 1/6
We need to borrow from the 8
We will borrow 1 from the 8 and make it a 7. The 1 will be written in the form 6/6
7 6/6
- 1 1/6
-----------------
6 5/6
