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Natalka [10]
3 years ago
12

Find the x-intercept for the line represented by this equation 7x=2y-3 A. (-3/7,0) B.(0,-3/7) C.(3/2,0) D.(0,3/2)

Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0

Answer: A

Step-by-step explanation:

For the x-intercept, we know y=0. We can eliminate B and D.

We know either A or C is the correct answer. This line is linear so there should be only one x-intercept. We can solve this equation to see which is correct. Let's plug in A and C into the equation to see which is right.

A. Correct

7(-\frac{3}{7} )=2(0)-3

-3=-3

C. Incorrect

7(\frac{3}{2} )=2(0)-3

\frac{21}{2}\neq  -3

Mnenie [13.5K]3 years ago
5 0

Answer:

(-3/7, 0)

Step-by-step explanation:

7x=2y-3

To find the x intercept, set y = 0 and solve for x

7x = 0-3

7x = -3

Divide each side by 7

7x/7 = -3/7

x = -3/7

The x intercept is

(-3/7, 0)

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Notice the picture below

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since the parabola is opening downwards, that means the "p" value is negative, so is -1

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}}) }\\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\

\bf \begin{cases}
p=-1\\
h=-2\\
k=5
\end{cases}\implies (x-(-2))^2=4(-1)(y-5)
\\\\\\
(x+2)^2=-4(y-5)\implies 
-\cfrac{1}{4}(x+2)^2=y-5
\\\\\\
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