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2 years ago

Work out the circumference of this circle.

Mathematics

1 answer:

worty [1.4K]2 years ago

6 0

<h3>given:</h3>

diameter= 13 cm

the circumference of the given circle.

<h3>solution:</h3>

$c = \pi \: d$

$c = 3.142 \times \: d$

$c = 3.142 \times 13$

$c = 40.846 \: cm$

hence, the circumference of the given circle is 40.846 cm

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Last month, Rhonda earned $3200. Of that amount, she spent $1350 on rent. What percent of her income went to rent, to the neares

Reika [66]

Divide 1350 by 3200.

1350 ÷ 3200 = 0.422

42.2% of her income went to rent.

6 0

3 years ago

Find the equation of a line parallel to the line x=-10 and contains the point (-4,4)

earnstyle [38]

Hello!

The line x = -10, is an example of an undefined line. It does not pass the vertical line test and each element of the domain is not paired with a unique (one and only one) element of the range. Remember that no two ordered pairs in a function have the same first element.

To find the line parallel to the line given line, we need to use the x-value in the given ordered pair, which will create the parallel line.

Therefore, the line parallel to the line x = -10 is x = -4.

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3 years ago

1.In the beautiful place of Sabang. Danao City we can see a lot of Coconut

MrRa [10]

Answer:

A) Number of mango trees

B) Percentage of coconut trees = 60%

Total number of trees = 2230 trees

C)number of mango trees = 40% × 2230

D) 892 mango trees

Step-by-step explanation:

A) What is asked is the number of mango trees

B) We are given;

Percentage of coconut trees = 60%

Total number of trees = 2230 trees

C) Number sentence is defined as when we use an equation or inequality to describe an expression using numbers and signs.

We have percentage of coconut trees = 60%.

Thus, percentage of mango trees = 100% - 60% = 40%

In this case, the number sentence is; number of mango trees = 40% × 2230

D) number of mango trees = 40% × 2230 = 892

5 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

Answer:

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

Solution:

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$