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xxTIMURxx [149]
2 years ago
12

Thank you!!!!!!!!!!!!!

Mathematics
1 answer:
SashulF [63]2 years ago
4 0

Answer:

y=\frac{4}{3}x+7

Step-by-step explanation:

y=-\frac{3}{4}x+1

Points: (12, 9)

Slope (m⊥): \frac{4}{3}

y=\frac{4}{3}x+b

9 = \frac{4}{3}(12)+b

9 = 16 + b

b = 7

y=\frac{4}{3}x+7

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Bx - cx<br>= c<br>solve for c​
VikaD [51]

Answer:

  c = bx/(x+1)

Step-by-step explanation:

Add cx to get c-terms together, and divide by the coefficient of c.

  bx = cx + c

  bx = c(x +1) . . . . factor out c

  bx/(x +1) = c

6 0
3 years ago
How many real solutions does this system of equations have? xy = 9<br> y = 3x - 1
tekilochka [14]

Answer:

two real, unequal roots

Step-by-step explanation:

y is definied as y = 3x - 1.  Substitute 3x - 1 for y in xy = 9, obtaining:

x(3x - 1) = 9.  Then:

3x^2 - x - 9 = 0.  In this quadratic, the coefficients are a = 3, b = -1 and c = -9.

Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

6 0
3 years ago
Item 7
topjm [15]

Answer:8,5 recirpoal is 5,8

Step-by-step explanation:

8 0
2 years ago
A UFO is coming in to pick up some test subjects. Their elevation above the ground is 60,000 feet. Their laser sights tell them
charle [14.2K]

Answer:

41.83°

Step-by-step explanation:

It is given that :

The vertical distance of the UFO from the ground = 60,000 feet

The diagonal distance of the landing area to the UFO = 90,000 feet

In order to find the angle of depression, we have to use the trigonometric ratios, i.e.,

$\sin \ \theta = \frac{\text{perpendicular distance}}{\text{hypotenus}}$

$\sin \ \theta = \frac{60,000}{90,000}$

$\sin \ \theta = \frac{2}{3}$

$\sin \ \theta = 0.667$

∴ $\theta = \sin^{-1 }(0.667)$

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3 0
3 years ago
Suppose that A, B, and C are invertible matrices of the same
STALIN [3.7K]

Answer:

Step-by-step explanation:

Given that t A, B, and C are invertible matrices of the same

size.

To pr that (ABC)^{-1} = C^{-1}B^{-1}A^{-1}.

to pr that  ( ABC) (C^{-1}B^{-1}A^{-1})=e

LS=( AB(C (C^{-1})B^{-1}A^{-1})\\=ABIB^{-1}A^{-1})\\=A(BB^{-1})A^{-1})\\=AA^{-1})\\=I

Thus proved

8 0
3 years ago
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