Algebra 2
2 answers:
Answer:
Step-by-step explanation:
n=sample size =200
Mean = x bar = 55 hours
Std deviation (Population) = 7 hours
For 99% confidence level
Z critical value = 2.58
Margin of error = ±2.58(std error)
Std error =
Hence margin of error = ±0.495(258)=1.28
Confidence interval = (55-1.28, 55+1.28) = (53.72, 56.28)
~(53.73, 56.27)
Hence option A
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The customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
<h3>How much cheese can she purchase?</h3>We are given with the cost of ham is $2.49 per pound and
Cost of swiss cheese is $3.79 per pound.
So, the cost of 2 pounds of ham will be given as-
= 2× $2.49
= $4.98
Since, the customer has a total of $9.50 to spend on 2 pounds of ham and some cheese,
∴ Let the number of pounds of cheese she can purchase be x.
Then the equation will be this:
2.49*2 + 3.79*x = 9.50
4.98 + 3.79x = 9.50
Subtracting 4.98 from each side we get-
4.98 -4.98 + 3.79x = 9.50-4.98
3.79x = 4.54
x
x = 1.19788 pounds of cheese (approximately 1.2 pounds).
Hence, the customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
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