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Norma-Jean [14]
3 years ago
9

A typical lap around the track in the United States has a length of 440 yard how many labs would you need to complete to run a m

ile
Mathematics
2 answers:
Artist 52 [7]3 years ago
4 0
The Answer is 4 laps
Kazeer [188]3 years ago
3 0
One mile is 1760 yards. So if you divide that by 440 you would get 4. So you would have to run around the track 4 times.
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A

Step-by-step explanation:

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There is 1,000 millimeters in mm

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Find the area and perimeter of a rectangle that has a length of (x + 24) and (x + 16). Show all work for full credit.
klio [65]

Answer:

Perimeter of rectangle = 4x + 80

Area = x² + 40x + 384

Step-by-step explanation:

Perimeter of rectangle = 2*(length + width)

                                      = 2* (x + 24 + x + 16)

                                      = 2*( x +x + 24 + 16)    {Combine like terms}

                                      = 2* (2x + 40)

Use Distributive property : a*(b +c) = a *b + a*c

                                     = 2*2x + 2*40

                                     = 4x + 80

Area of rectangle = length * width

                             = (x + 24) (x + 16) {use FOIL method}

                            = x*x + x*16 + 24*x + 24*16

                             = x² + 16x + 24x + 384  {Combine like terms}

                             = x² + 40x + 384

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3 years ago
The probability of pulling an orange is 2 out of 5 if I 20 times how many of them would be orange
telo118 [61]
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3 years ago
Find the coordinates of the midpoint of a segment having the given endpoints.
inysia [295]

Answer:

A. (1.55, 2)

Step-by-step explanation:

The formula to apply when finding the midpoint of a segment where the coordinates of the end points are given is;

midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

where (x₁,y₁) and (x₂,y₂) are the coordinates of the end points

Given;

x₁= -0.4 ,y₁=2.5,  x₂=3.5, y₂=1.5 then applying the formula for midpoint

=(\frac{-0.4+3.5}{2} ,\frac{2.5+1.5}{2} )\\\\\\=(\frac{3.1}{2} ,\frac{4.0}{2} )\\\\\\=(1.55,2.0)

3 0
3 years ago
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